Question

Complete and balance the equation for the combustion of zns in excess oxygen ? zns + ? o2→ ? zno + ? use no fractional coefficients. the number of moles and the formula of the product containing s are

Answer 1

The combstion of ZnS in excess oxygen gives ZnO and SO₂ as the products.
hence the equation should be;

                   ZnS(s) + O₂(g) →ZnO(s) + SO₂(g)

At the left hand side:                               At the right hand side:
number of Zn atoms = 1                               number of Zn atoms = 1
number of S atoms = 1                                 number of S atoms = 1
number of O atoms = 2                                number of O atoms = 3

Hence the balanced equation is;
           2ZnS(s) + 3O₂(g) →2ZnO(s) + 2SO₂(g)