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daser333 [38]
4 years ago
8

What kind of charge would the oxygen atom have compared to the hydrogen atoms

Chemistry
1 answer:
Oliga [24]4 years ago
8 0
It should be charge 2-they lose electrons
You might be interested in
Why does oxygen have stronger attractive forces between its nucleus and valence electrons than nitrogen?
Marina86 [1]
The higher the amount of protons, the higher the amount of attraction, and the higher the attraction, the higher the electronegativity. N has 7, and O has 8. Therefore Oxygen has a higher level of electronegativity
4 0
3 years ago
A 12.8-g sample of sodium completely reacts with 19.6 g of chlorine to form 32.4 g of sodium chloride. These data are A 12.8-g s
coldgirl [10]

Answer: The data are consistent with the law of conservation of mass because the mass of reactants equals the mass of products

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

Given: mass of sodium = 12.8 g

mass of chlorine = 19.6 g

mass of reactants = mass of sodium + mass of chlorine = 12.8 g + 19.6 g = 32.4 g

Mass of product = Mass of sodium chloride = 32.4 g

As mass of reactant = mass of products , Thus results are in accordance with the law of conservation of mass.​

5 0
3 years ago
How an atom chemically behaves when it comes into contact with other?
nlexa [21]
It is determined by its ELECTRIC CONFIGURATION.
5 0
3 years ago
MASTERING CONCEPTS<br> 31. List three examples of substances. Explain why each<br> is a substance.
SOVA2 [1]

Answer:

vc

Explanation:

cvcv

6 0
3 years ago
1125 J of energy is used to heat 250 g of iron to 55 °C. The specific heat capacity of iron is 0.45 J/(g·°C).
Stolb23 [73]

Answer:

45 °C.

Explanation:

From the question given above, the following data were obtained:

Heat (Q) = 1125 J

Mass (M) = 250 g

Final temperature (T₂) = 55 °C

Specific heat capacity (C) = 0.45 J/gºC

Initial temperature (T₁) =?

The initial temperature of the iron can be obtained as illustrated below:

Q = MC(T₂ – T₁)

1125 = 250 × 0.45 (55 – T₁)

1125 = 112.5 (55 – T₁)

Divide both side by 112.5

1125/112.5 = 55 – T₁

10 = 55 – T₁

Collect like terms

10 – 55 = –T₁

–45 = –T₁

Multiply through by –1

45 = T₁

T₁ = 45 °C

Therefore, the initial temperature of the iron is 45 °C

8 0
3 years ago
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