Answer:
we need a picture...
Step-by-step explanation:
Sin D=35/37
cos D=12/37
tan D= 35/12
Use SOHCAHTOA
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Answer:
time to max height: 2.5 seconds
max height: 104 ft
range of function: [4, 104]
Step-by-step explanation:
The equation for ballistic motion is ...
h(t) = -16t^2 +v0·t +h0 . . . . where v0 is the initial upward speed and h0 is the initial height
For the given parameters, the height function is ...
h(t) = -16t^2 +80t +4
The time for maximum height is ...
-b/(2a) = -80/(2(-16)) = 2.5 . . . seconds
The maximum height is ...
h(2.5) = (-16·2.5 +80)(2.5) +4 = 104 . . . feet
The range of the function is from the minimum height (at launch) to the maximum height:
4 ft ≤ h(t) ≤ 104 ft.
Assuming you know the quadratic formula:

You can fill in a, b and c in this and get:

Now, let's create a shorthand
to make the writing easier:

But since one root is three times the other root (but we don't know which one), we also know that:
or 
If you solve this, you get:
or 
However, since q is a square root, it must be postive.
So we know that:

From this you find that

So p = 3/2
The roots are x=1/2 and x=3/2.
The answer is 14 (D).
14 halved is 7.
7 is greater than or equal to 7.