Answer:
30 ft
Step-by-step explanation:
Hi!
So according to the Pythagorean theorem, a^2 + b^2 = c^2
Ok, so let's just plug those numbers in:
18^2 + 24 ^ 2 = c^2
324 + 576 = c^2
900 = c^2
= c
= 30
x = 30
You could also use Pythagorean triples, and there are Pythagorean triples for this which is 3:4:5; and since it's a ratio, we can write it as 3x:4x:5x. Then, according to a and b, x would equal 6, so then we plug in x:
3(6):4(6):5(6)
and you get:
18:24:30
Let me know if you have any questions.
Answer:
-10
Step-by-step explanation:
Answer:
First question: LCL = 522, UCL = 1000.5
Second question: A sample size no smaller than 418 is needed.
Step-by-step explanation:
First question:
Lower bound:
0.36 of 1450. So
0.36*1450 = 522
Upper bound:
0.69 of 1450. So
0.69*1450 = 1000.5
LCL = 522, UCL = 1000.5
Second question:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

The project manager believes that p will turn out to be approximately 0.11.
This means that 
95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The project manager wants to estimate the proportion to within 0.03
This means that the sample size needed is given by n, and n is found when M = 0.03. So






Rounding up
A sample size no smaller than 418 is needed.
That will be A bc B is much longer than A