Answer:

Step-by-step explanation:
In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).
The formula we will use for this problem is the following:

where:


a=0

so the volume becomes:

This can be simplified to:

and the integral can be rewritten like this:

which is a standard integral so we solve it to:
![V=9\pi[tan y]\limits^\frac{\pi}{3}_0](https://tex.z-dn.net/?f=V%3D9%5Cpi%5Btan%20y%5D%5Climits%5E%5Cfrac%7B%5Cpi%7D%7B3%7D_0)
so we get:
![V=9\pi[tan \frac{\pi}{3} - tan 0]](https://tex.z-dn.net/?f=V%3D9%5Cpi%5Btan%20%5Cfrac%7B%5Cpi%7D%7B3%7D%20-%20tan%200%5D)
which yields:
]
It's C.......................
I hope this helps you
if he can earn $9 per hour
$405 ? hours
?=405/9
?=45 hours he worked
Answer:Solution:
Let starting map of youth center has Dimension (Preimage)
1 unit of y= k units
1 unit of x = t units
The new map of youth center which is 3 times larger than original(Image)
1 unit of y= 3 k units
1 unit of x = 3 t units
Image = 3 × Pre- image
The image is larger than Pre- image.
So, Scale of the new map = 3 × The original dimension of map.
Step-by-step explanation:
Answer:
Step-by-step explanation:
First convert them into improper fractions:
and
. Now we add:
or
.