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aniked [119]
3 years ago
9

While visiting a friend's home, I saw kittens and chickens playing in the backyard. Counting heads, I got 18. Counting feet, I g

ot 50. How many kittens and how many chickens were in the backyard?
Mathematics
1 answer:
andrew11 [14]3 years ago
5 0

Answer:

  11

Step-by-step explanation:

The 25 pairs of feet were 7 more than the number of heads, so there were 7 kittens. Hence there were 18-7 = 11 chickens.

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I believe its the second choice.
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Compute the following products.<br> (4x+5)(4x−5)<br><br> (4x+5)2
bearhunter [10]
(4x+5)(4x-5) is equal to 16x^2+20x-20x-25
The positive and negative 20x cancel out
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[S/N this is a pattern that shows up a decent amount. Whenever you have something that looks like (x^2-y^2) it factors out to (x+y)(x-y). It might be helpful to remember]

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2 years ago
Please answer! I’ll give you Brainliest
Sergio [31]

A)

The four small squares are all 3x3, so the perimeter is 3+3+3+3 = 12.

12 * 4 = 48

We can find the perimeter of the large diamond shape using the Pythagorean theorem, a^2 + b^2 = c^2

a = 4

b = 4

4^2 + 4^2 = c^2

16 + 16 = c^2

32 = c^2

c = 5.65685425

So the perimeter of the large diamond shape is

5.65685425+5.65685425+5.65685425+5.65685425 = 22.627417

48+22.6 = 70.6

B)

The areas of the small squares are 3x3 = 9

9 * 4 = 36

The area of the large diamond shape is

5.65685425 * 5.65685425 = 32

36 + 32 = 68

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2 years ago
Identify a line that looks like a number line
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|------|------|------|-----|------|
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Answer:

1) x is negative and y is positive ⇒ last answer

2) cotФ = -12/35 ⇒ second answer

3) The right identity is cot²Ф - csc²Ф = -1 ⇒ last answer

Step-by-step explanation:

* For any point (x , y) lies on the terminal side of the angle Ф

 in standard position

* x = cosФ and y = sinФ

- If Ф in the first quadrant, then x , y are positive

∴ All trigonometry functions are positive

- If Ф in the second quadrant, then x is negative , y is positive

∴ sinФ only is positive

- If Ф in the third quadrant, then x is negative , y is negative

∴ tanФ only is positive

- If Ф in the fourth quadrant, then x is positive , y is negative

∴ cosФ only is positive

* Lets solve the problems

∵ Ф = 3π/4 ⇒ (135°)

∴ It lies on the second quadrant

∴ x is negative and y is positive

* Lets revise the reciprocal of sinФ, cosФ and tanФ

- cscФ = 1/sinФ

- secФ = 1/cosФ

- cotФ = 1/tanФ

∵ secФ = -37/12

∴ cosФ = -12/37

∵ π/2 < Ф < π

∴ Ф lies on the second quadrant

∴ cotФ is negative values

∵ tan²Ф = sec²Ф - 1

∵ secФ = -37/12

∴ tan²Ф = (-37/12)² - 1 = 1225/144 ⇒ take√ for both sides

∴ tanФ = ± 35/12

∵ cotФ = ± 12/35

∵ cotФ is negative value

∴ cotФ = -12/35

* In the standard position of the angle Ф the terminal

 of it lies on the unit circle O

- By using Pythagorean theorem

∵ x² + y² = 1

∵ x = cosФ and y = sinФ

∴ cos²Ф + sin²Ф = 1 ⇒ (1)

∴ cos²Ф = 1 - sin²Ф

∴ sin²Ф = 1 - cos²Ф

* Divide (1) by cos²Ф

∴ cos²Ф/cos²Ф + sin²Ф/cos²Ф = 1/cos²Ф

* Remember sin²Ф/cos²Ф = tan²Ф and 1/cos²Ф = sec²Ф

∴ 1 + tan²Ф = sec²Ф ⇒ (2) ⇒ subtract 1 from both sides

∴ tan²Ф = sec²Ф - 1 ⇒ subtract sec²Ф from both sides

∴ tan²Ф - sec²Ф = -1

* Divide (1) by sin²Ф

∴ cos²Ф/sin²Ф + sin²Ф/si²Ф = 1/sin²Ф

* Remember cos²Ф/sin²Ф = cot²Ф and 1/sin²Ф = csc²Ф

∴ cot²Ф + 1 = csc²Ф ⇒ (3) ⇒ subtract 1 from both sides

∴ cot²Ф = csc²Ф - 1 ⇒ subtract csc²Ф from both sides

∴ cot²Ф - csc²Ф = -1

* The right identity is cot²Ф - csc²Ф = -1

3 0
3 years ago
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