Question

Help please?????///////////////////////////////////

Answer 1

Answer:

  3; all real numbers except x = 2

Step-by-step explanation:

$\dfrac{f(x)}{g(x)}=\dfrac{3x-6}{x-2}=\dfrac{3(x-2)}{(x-2)}=3 \qquad x\ne 2$

Answer 2

Answer:

B

Step-by-step explanation:

f(x) can be factored from f(x) = 3x-6 into f(x) = 3(x-2). Divide f by g in a fraction now.

$\frac{f(x)}{g(x)}= \frac{3(x-2)}{x-2} =\frac{3}{1}*\frac{x-2}{x-2} =3$

Since anything divided by itself is 1 then x-2 divided by x-2 is 1 leaving 3 as the answer. This leaves a or b. The answer is b because the division cannot happen if the denominator is 0. So x-2 cannot ever be 0. It's 0 when x=2. The answer is b.