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alexdok [17]
3 years ago
9

Determine the function which corresponds to the given graph. (3 points)

Mathematics
1 answer:
damaskus [11]3 years ago
6 0

Answer:

The center of the circle is c=50 and radius of the circle is r=\sqrt{3}

Step-by-step explanation:

Given circle equation is

x^2-4x+y^2+14y=-50\hfill(1)

Equation (1) can be written as x^2-4x+y^2+14y+50=0\hfill(2)

we know that the equation of the circle is of the form

x^2+y^2+2gx+2fy+c=0\hfill(3)

with centre (-g,-f) and radius=\sqrt{g^2+f^2-c}

when, g,f and c are constants

Now comparing the (2) and (3) equations we get 2g=-4

                                                                          g=\frac{-4}{2}

                                                                          g=-2

                                                                          2fy=14

                                                                          f=\frac{14}{2}

                                                                          f=7

                                                                 and  c=50

Now to find the centre and radius of the given circle equation, substituting the values of g,f,c in the formulae of centre and radius

                  centre=(-g,-f)

                             =(-(-2),-7)

                  centre=(2,7)

                  Radius=\sqrt{g^2+f^2-c}

                              =\sqrt{(-2)^2+(7)^2-50}

                             =\sqrt{4+49-50}

                            =53-50

                   Radius=\srqt{3}

The center of the circle is c=50 and the radius of the circle equation r=\sqrt{3}

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