Answer:
a is 39
b is 57
Step-by-step explanation:
you were given two different expressions to substitute.
the first one is p = 8 and d = 1/7
so we substitute into 5p - 7d
that is 5(8) - 7(1/7)
we get 40 - 1
which if we go ahead to evaluate we get 39
The second one p = 3 and d = -6
so we get 5(3) - 7(-6)
we get 15 - (-42)
if we go ahead to evaluate we get 15 + 42
two negative meeting each other gives you positive.
then it going too be 57
Answer:
4.
A = arcsin(BC/AB) = arcsin(4/10) = ~23.58 deg
B = arccos(BC/AB) = arccos(4/10)= ~66.42 deg
AC = sqrt(AB^2-BC^2) = sqrt(10^2-4^2) = 9.16
5.
A = 90-B=90-20 =70
AB = AC/sinC = 30/sin(20deg) = ~87.71
BC = sqrt(AB^2-AC^2) = sqrt(87.71^2-30^2) = ~82.42
6.
AB = AC/cosA =125/cos(50deg) = ~194.46
B = 90-A = 90-50 =40
BC = sqrt(AB^2-AC^2) = sqrt(194.46^2-125^2) = ~148.96
7.
AB = AC/cosA =8/cos(20deg) = ~8.51
B=90-A =90-20=70
BC = sqrt(AB^2-AC^2) = sqrt(8.51^2-8^2) =~2.90
Answer:
The standard deviation of the sampling distribution would change by a factor of 
Step-by-step explanation:
We use the central limit theorem to solve this question.
The Central Limit Theorem estabilishes that, for a random variable X, with mean 
and standard deviation 
, a large sample size can be approximated to a normal distribution with mean and standard deviation 
In this problem, we have that:
The standard deviation of the population is 
Sample size n
Sample size 2n
What factor would the standard deviation of the sampling distribution of change?
So the standard deviation of the sampling distribution would change by a factor of
