Ask question

Ask question

All categories

aleksklad [387]

2 years ago

12

Mr. Bobby plans to spend no more than $200 on pizza and soda for a party. Each pack of soda costs $5.00 and each pizza costs $8.

00. Which inequality could Mr. Bobby use to determine how many packs of soda, s, and how many pizzas, p, he can buy?

2 answers:

goldfiish [28.3K]2 years ago

4 0

Answer:

6yr

Step-by-step explanation:

7t

Debora [2.8K]2 years ago

4 0

Answer:

6y

Step-by-step explanation:

You might be interested in

3. Find the mean and the median of this data set: 9,6,5, 3, 28, 6, 4, 7.<br>

BARSIC [14]

Answer:

Mean= 8.5

Median= 6

Step-by-step explanation:

3,4,5,6,6,7,9,28

Median= Middle (If two middle number, add and divide by 2)

Mean= (3+4+5+6+6+7+9+28) ÷8

7 0

3 years ago

Let Y be a random variable with a density function given by

Neporo4naja [7]

From the given density function we find the distribution function,

$F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y$

(a)

$F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)$

$\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1$

$\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}$

(b)

$F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y$

$\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2$

$\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}$

(c)

$F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})$

$\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3$

$\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}$

5 0

2 years ago

Select all the true statements

Dennis_Churaev [7]

Answer:

option no (C) is correct

Step-by-step explanation:

4 0

2 years ago

HELP QUICK PLEASE!!!! 20PTS!!!!!

Alexxx [7]

Answer:

3

Step-by-step explanation:

3 is a function because of the way associated with the second set

3 0

2 years ago

An apple grower finds that if he plants 80 trees per acre, each tree will yield 26 bushels of fruit. He estimates that for each

hammer [34]

Answer: The maximum revenue is $7482 . To get a maximum yield , The number of trees per acre needed is 43.

Step-by-step explanation:

Solution:

Let x represent the extra tree

So for an additional tree the yield of each tree will decrease by 4 bushels.

(80 +x)(26-4x) by expanding

2080 - 320x +26x -4x^2

Using x= -b/2a

X= 294/ -8

X= - 36.75

So apparently he currently has far too many trees per acre. To get the maximum yield , she needs to reduce the number of trees per acre by 36.75

So the number of trees per acre for maximum yield is

80-36.75

=43.25

Approximately x=43

So by reducing he get extra bushel in the tune of 174.

Total revenue= 174 ×43× 1$

=$7482

3 0

3 years ago