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3 years ago

Which statement best describes the collisions of gas particles according to the kinetic-molecular theory?

Chemistry

2 answers:

In-s [12.5K]3 years ago

5 0

Answer:

As particles travel in straight lines, their paths sometimes meet, and then they bounce apart with no gain or loss of energy.

Explanation:

Was right on edge

Andrew [12]3 years ago

3 0

Answer:

b. As particles travel in straight lines, their paths sometimes meet, and then they bounce apart with no gain or loss of energy.

Explanation:

Kinetic - molecular theory -

According to this theory , gas is considered to be as a large number of very small particles , which moves randomly , and due to this randomness collisions occurs , as the particles collide with each other and the wall of the container .

During these collisions , there is no loss or gain of energy , there is only transfer of energy .

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The balanced equation for the reaction of aqueous Pb(ClO3)2 with aqueous NaI is Pb(ClO3)2(aq)+2NaI(aq)⟶PbI2(s)+2NaClO3(aq) What

ryzh [129]

Answer : The mass of $PbI_2$ precipitate produced will be, 9.681 grams.

Explanation : Given,

Molarity of NaI = 0.210 M

Volume of solution = 0.2 L

Molar mass of $PbI_2$ = 461.01 g/mole

First we have to calculate the moles of $NaI$ .

$\text{Moles of }NaI=\text{Molarity of }NaI\times \text{Volume of solution}=0.210M\times 0.2L=0.042moles$

Now we have to calculate the moles of $PbI_2$ .

The balanced chemical reaction is,

$Pb(ClO_3)_2(aq)+2NaI(aq)\rightarrow PbI_2(s)+2NaClO_3(aq)$

From the balanced reaction we conclude that

As, 2 moles of $NaI$ react to give 1 mole of $PbI_2$

So, 0.042 moles of $NaI$ react to give $\frac{0.042}{2}=0.021$ moles of $PbI_2$

Now we have to calculate the mass of $PbI_2$ .

$\text{Mass of }PbI_2=\text{Moles of }PbI_2\times \text{Molar mass of }PbI_2$

$\text{Mass of }PbI_2=(0.021mole)\times (461.01g/mole)=9.681g$

Therefore, the mass of $PbI_2$ precipitate produced will be, 9.681 grams.

6 0

4 years ago

What is units we used for measuring the radon gas?

lisabon 2012 [21]

Answer:

Bq/m3 (becquerels per cubic meter) or pCi/l (picocuries per litre)

Explanation:

The unit of the International System of Units identified to measure radioactive activity is Becquerelio (Bq) and equivalent to one decay per second.

The Curio (Ci) is also a radioactivity unit, which is still being used in some countries. It owes its name to chemists and chemists Pierre and Marie Curie.

It represents the amount of material in which 3.7 × 1010 atoms per second, or 3.7 × 1010 nuclear decays per second, which is roughly the activity of 1 g of 226Ra (isotope of the chemical chemical element).

The equivalence between the two is:

1Ci= 3,7 × 1010Bq

The specific radioactive activity of a radioactive gas such as radon gas is measured per unit volume and measured in Bq/m3 or pCi/l.

In this case the equivalence is:

1pCi/l= 37Bq/m3

6 0

4 years ago

Can someone please help me

Nezavi [6.7K]

Answer:

I would say w is the answer

4 0

3 years ago

Read 2 more answers

An analytical chemist weighs out 0.281g of an unknown diprotic acid into a 250mL volumetric flask and dilutes to the mark with d

Helen [10]

Answer:

166 g/mol

Explanation:

Step 1: Write the neutralization reaction

H₂A + 2 NaOH ⇒ Na₂A + 2 H₂O

Step 2: Calculate the reacting moles of NaOH

48.3 mL of 0.0700 M NaOH react.

0.0483 L × 0.0700 mol/L = 3.38 × 10⁻³ mol

Step 3: Calculate the reacting moles of H₂A

The molar ratio of H₂A to NaOH is 1:2. The reacting moles of H₂A are 1/2 × 3.38 × 10⁻³ mol = 1.69 × 10⁻³ mol.

Step 4: Calculate the molar mass of H₂A

1.69 × 10⁻³ moles of H₂A have a mass of 0.281 g. The molar mass of H₂A is:

M = 0.281 g / 1.69 × 10⁻³ mol = 166 g/mol

6 0

3 years ago

The density of gold is approximately .1785 g/L. What is the mass of a sample of helium that occupies 50.0 L of space? Round your

Olegator [25]

What is the purpose for golds density?

7 0

3 years ago