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tino4ka555 [31]
3 years ago
7

125 cm3 of a solution contains 0.25 moles of the solute. What is the concentration of the solution?

Chemistry
1 answer:
jarptica [38.1K]3 years ago
3 0

Answer:

Explanation:

125 cm3 -> 0.125 L

M = no. mole / volume (L)

M = 0.25 / 0.125 = 2 M

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In the sodium-potassium pump, sodium ion release causes two K ions to be released into the cell. __________________ True False
Solnce55 [7]

Answer:

false

Explanation:

As we know that in sodium-potassium pump .          

sodium potassium move 3Na+ outside the cells          

and  moving 2k+ inside the cells                        

so that we can say that given statement is false    

Answer FALSE                                                      

6 0
2 years ago
a solution of prepared by dissolving 20.0 brams of mavni fluride (MgF2) in 80.0 of water (H2O). whag is the mole fraction of mag
Serjik [45]

Answer:

2000.1234 trebuie sa fie asa

3 0
3 years ago
In the reaction N2 + 3H2 → 2NH3, what is the mole ratio of hydrogen to nitrogen?
uranmaximum [27]

Answer: The mole ratio of hydrogen to nitrogen is 3 mole: 1 mole, 3:1

Explanation:

•Mole ratios are determined using the coefficients of the substances in the balanced chemical equation. •Each coefficient represents the number of mole of each substance in the chemical reaction.

•The mole ratio can be determined by first writing out a balanced chemical equation for the reaction.

For this reaction the balanced chemical equation is

N2(g) + 3H2(g) ----> 2NH3(g)

1mol:3mol : 2mol

From the equation we can see that 1 mole of N2(g) reacts with 3 moles of H2(g) or 3 moles of H2(g) react with 1 mole of N2(g) to produce 2 moles of NH3(g).

Therefore, the mole ratio of hydrogen to nitrogen is 3 mole: 1 mole, 3:1

7 0
3 years ago
Lithium diisopropylamide (LDA) is used as a strong base in organic synthesis. LDA is itself prepared by an acid-base reaction be
kakasveta [241]

Explanation:

Lithium diisopropylamide (LDA) is used in many organic synthesis and is a strong base. It is prepared by the acid base reaction of N,N-diisopropylamine ( [(CH₃)₂CH]₂NH ) and butyllithium ( Li⁺⁻CH₂CH₂CH₂CH₃ ).

The equation is show below as:

[(CH₃)₂CH]₂NH + Li⁺⁻CH₂CH₂CH₂CH₃  ⇒  [(CH₃)₂CH]₂N⁻Li⁺  + CH₃CH₂CH₂CH₃

N,N-diisopropylamine ( [(CH₃)₂CH]₂NH ) is a weaker acid and hence,  LDA ( [(CH₃)₂CH]₂N⁻Li⁺ ) is stronger base. (Weaker acid has stronger conjugate base)

Butyllithium ( Li⁺⁻CH₂CH₂CH₂CH₃ ) is a very strong base and hence, butane ( CH₃CH₂CH₂CH₃ ) is a very weak acid. (Strong base has weaker conjugate acid)

5 0
3 years ago
A buffer is made by dissolving H3PO4 and NaH2PO4 in water.
xeze [42]

Answer:

(a) H₃O⁺(aq) + H₂PO₄⁻(aq) ⟶ H₃PO₄(aq) + H₂O(ℓ)

(b) OH⁻(aq) + H₃O⁺(aq) ⟶ 2H₂O(ℓ)

Explanation:

The equation for your buffer equilibrium is:

H₃PO₄(aq) + H₂O(ℓ) ⇌ H₃O⁺(aq)+ H₂PO₄⁻(aq)

(a) Adding H₃O⁺

The hydronium ions react with the basic dihydrogen phosphate ions.

H₃O⁺(aq) + H₂PO₄⁻(aq) ⟶ H₃PO₄(aq) + H₂O(ℓ)

(b) Adding OH⁻

The OH⁻ ions react with the more acidic hydronium ions.

OH⁻(aq) + H₃O⁺(aq) ⟶ 2H₂O(ℓ)

4 0
3 years ago
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