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wolverine [178]
3 years ago
12

When Alex bought his new car in 2006, it was worth $28,350. In 2015, it was worth a third of its original value. Find the percen

t of change in the value of the car from 2006 to 2015.
Mathematics
1 answer:
agasfer [191]3 years ago
3 0
Hey tbh I don’t know but everything is going to be ok
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Who do you write a function
melamori03 [73]
You can determine what variable your function depends upon. In the example of y = 2x + 6, the function changes as the value of x changes, so the function is dependent upon x. The left side of your function is the name of your function followed by the dependent variable in parentheses, f(x) for the example.
8 0
3 years ago
Given that<br>9^-1/2 = 27^1/4 ÷ 3^x+1<br>Find the exact value of x. ​
nexus9112 [7]

Answer:

Find the exact value using trigonometric identities.

Exact Form: x=34

Decimal Form: x=0.75

Step-by-step explanation:

5 0
3 years ago
Briooooo wat is dis answer I need HELP
Harrizon [31]

Answer:

Mehmed II

Step-by-step explanation:

5 0
3 years ago
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Evaluate the expression when y = 3 <br> B.) 12y
Archy [21]
12y = 12*3 = 36  ← answer
3 0
3 years ago
Please solve the problem with steps
Debora [2.8K]

Answer:

Infinite series equals 4/5

Step-by-step explanation:

Notice that the series can be written as a combination of two geometric series, that can be found independently:

\frac{3^{n-1}-1}{6^{n-1}} =\frac{3^{n-1}}{6^{n-1}} -\frac{1}{6^{n-1}} =(\frac{1}{2})^{n-1} -\frac{1}{6^{n-1}}

The first one: (\frac{1}{2})^{n-1} is a geometric sequence of first term (a_1) "1" and common ratio (r) " \frac{1}{2} ", so since the common ratio is smaller than one, we can find an answer for the infinite addition of its terms, given by: Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{2} } =\frac{1}{\frac{1}{2} } =2

The second one: \frac{1}{6^{n-1}} is a geometric sequence of first term "1", and common ratio (r) " \frac{1}{6} ". Again, since the common ratio is smaller than one, we can find its infinite sum:

Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{6} } =\frac{1}{\frac{5}{6} } =\frac{6}{5}

now we simply combine the results making sure we do the indicated difference: Infinite total sum= 2-\frac{6}{5} =\frac{10-6}{5} =\frac{4}{5}

8 0
3 years ago
Read 2 more answers
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