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3 years ago

The sides of a triangle are in the ratio 2:3:5. The perimeter of the triangle is 55

Mathematics

1 answer:

Lynna [10]3 years ago

7 0

Answer:

The length of each sides are 11 feet, 16.5 feet, 27.5 feet.

Step-by-step explanation:

The ratio of the sides of a triangle are 2:3:5.

The sides of the triangle = 2x, 3x, 5x

The perimeter of the triangle = 55 feet.

2x + 3x + 5x = 55

10x = 55

x = 55/10 = 5.5

Length of each side : 2x = 2*5.5 = 11 feet

3x = 3*5.5 = 16.5 feet

5x = 5 * 5.5 = 27.5 feet

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The population of West Algebra can be modeled by the equation

AleksAgata [21]

Answer:

65.7

Step-by-step explanation:

Given the population of West Algebra can be modeled by the equation

P = 30. 1.04^T

If T is the number of years since 2000 and P is the population in millions, in 2020, T = 2020 - 2000 = 20

Substitute T = 20 into the expression and get T

P = 30. 1.04^20

P = 30(2.1911)

P = 65.73

Hence the amount of people that will be there in 2020 is 65.7million people

6 0

3 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

3 years ago

An equilateral triangle is a triangle that has three sides of the same length. the perimeter of an equilateral triangle is 48.6

aleksklad [387]

We know that a triangle has three sides, all the same length (its equilateral, after all)

The equation to find the length of each side is

Perimeter divided by 3

or in this case

48.6 divided by 3=16.2cm (don't forget the unit)

Hope that helps :)

3 0

3 years ago

Read 2 more answers

I need help this is 6th grade Question 3×(5+4^2)-10

bonufazy [111]

Using PEMDAS the you start with parentheses and exponents 4x4 would be 16 times 2 is 32 plus 5 is 37 then multiply that by 3 = 111 subtract 10 and get 101

8 0

3 years ago

Line AB passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to

MArishka [77]

I hope this helps you

slope = 5-0/-6-(-3)= -5/3

(0,0)

m.(x1-x)=y1-y

-5/3.(0-x)=0-y

5x= -3y

5x+3y=0

4 0

3 years ago