The equation of the function is y = sec(2(x + π/6)) + 2
<h3>How to determine the equation of the function?</h3>
The graph that completes the question is added as an attachment
From the attached graph, we have the following parameters:
- Local maximum = 3
- Local minimum = 1
- Period = 2
- Phase shift = π/6
A secant function is represented as:
y = A sec(b(x + c)) + d
Where:
A = 0.5 * (max - min) = 0.5 * (3 - 1) = 1
b = Period = 2
c = Phase shift = π/6
d = 0.5 * (max + min) = 0.5 * (3 + 1) = 2
Substitute these values in y = A sec(b(x + c)) + d
y = 1 * sec(2(x + π/6)) + 2
Evaluate
y = sec(2(x + π/6)) + 2
Hence, the equation of the function is y = sec(2(x + π/6)) + 2
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Then divide 95/3. that will give you 31.6repeating
Answer:
28.8 ft
Step-by-step explanation:
SOH CAH TOA reminds you that ...
Tan = Opposite/Adjacent
The height to the top of the antenna is opposite the angle of elevation, and the distance to the building is adjacent. So, we have ...
tan(58°) = (160 ft +antenna height)/(118 ft)
(118 ft)·tan(58°) = 160 ft + antenna height . . . . . . . multiply by 118 ft
188.8 ft - 160 ft = antenna height = 28.8 ft . . . . . . subtract 160 ft, evaluate
The height of the antenna is 28.8 ft above the top of the building. (The total height of building + antenna is 188.8 ft.)
Answer:
y = (5/7)x + 3
Step-by-step explanation:
We use the form y = mx + b. Substituting (5/7) for m, 7 for x and 8 for y, we get:
8 = (5/7)(7) + b, or 8 = 5 + b. Thus, b = 3, and the desired equation is
y = (5/7)x + 3