Using the z-distribution, it is found that the 90% confidence interval is given by: (0.6350, 0.6984).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:
In which:
- is the sample proportion.
In this problem, we have a 90% confidence level, hence, z is the value of Z that has a p-value of , so the critical value is z = 1.645.
The sample size and the estimate are given by:
Hence, the bounds of the interval are given by:
The 90% confidence interval is given by: (0.6350, 0.6984).
More can be learned about the z-distribution at brainly.com/question/25890103
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Im not sure, when in doubt pick C
Answer:
2
Step-by-step explanation:
-3 log₂ (-n + 10) = -16+7
-3 log₂ (-n + 10) = -9
log₂ (-n + 10) = -9/-3
log₂ (-n + 10) = 3
-n + 10 = 2^3
-n + 10 = 8
n=2
Answer: x-intercept 13,0 y 0,
Step-by-step explanation: