Answer:
Step-by-step explanation:
Since this is a right triangle, we will use a right triangle trig identity to solve our problem. The side opposite the reference angle A is given as 5, and the side adjacent to the reference angle is given as 7. The trig ratio that uses the sides opposite and adjacent is the tangent ratio:
Hit the 2nd button on your calculator then the tan button which displays:
Enter 5/7 after that open parenthesis and hit = to get that
A = 35.54°
Answer:
31.5 kilograms of a 5% salt solution and 13.5 kilograms of a 15% salt solution must be mixed together to make 45kg of an 8% salt solution .
Step-by-step explanation:
Let us assume that the number of kilograms of a 5% salt solution used be x .
Let us assume that the number of kilograms of a 15% salt solution used be y .
As given
A 5% salt solution and 15% salt solution must be mixed together to make 45kg of an 8% salt solution .
Equation becomes
x + y = 45
5% is written in the decimal form .
= 0.05
15% is written in the decimal form .
= 0.15
8% is written in the decimal form .
= 0.08
Thus
Concentration of 5% salt solution × Number of kilograms of 5% salt solution used + Concentration of 15% salt solution × Number of kilograms of 15% solution used = Concentration of 8% salt solution × Number of kilograms of 8% salt solution
Thus
0.05x + 0.15y = 0.08 × 45
Simplify the above
5x + 15y = 360
Thus two equations becomes
x + y = 45
5x + 15y = 360
Multiply x + y = 45 by 5 and subtracted from 5x + 15y = 360 .
5x - 5x + 15y - 5y = 360 - 225
10y = 135
y = 13.5 kilograms
Put value of y in the equation
x + 13.5 = 45
x = 45 - 13.5
x = 31.5 kilograms
Therefore the 31.5 kilograms of a 5% salt solution and 13.5 kilograms of a 15% salt solution must be mixed together to make 45kg of an 8% salt solution .
The distance, in units, from the school to the library and then the distance from the library to the park is 15 units.
<h3>What is the length of any line on the graph?</h3>The distance or length of any line on the graph,
D = √{(x₂ - x₁)² + (y₂ - y₁)²}
where,
d = distance/length of the line between point 1 and 2,
(x₁ , y₁) = coordinate of point 1,
(x₂ , y₂) = coordinate of point 2,
The distance from school to the library is SL, therefore,
The distance from library to the park is LP, therefore,
Now, the distance, in units, from the school to the library and then the distance from the library to the park is 15 units (10 units + 5 units).
Learn more about the Length of the line:
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