Answer:
The answer to your question is
Part A. Archimedes grades 6 1/4 tests per day
Part B. 8 19/32 days
Part C. 6 26/29 days
Step-by-step explanation:
Part A
Total time = 6 2/5 days
Number of tests = 40 tests
Process
1.- Convert the mixed fraction to improper fraction
6 2/5 = (30 + 2) / 5 = 32/5
2.- Divide 40 by 32/5
40/1 / 32/5 = (40 x 5) / (32 x 1)
= 200 / 32
Simplify
100 / 16 = 50/8 = 25/4
3.- Convert 25/4 to mixed fractions
6
4 25
1
25/4 = 6 1/4
Archimedes grade 6 1/4 tests per day
Part B
15 more tests
Total time = 32/5
Total tests = 40 + 15 = 55
Process
1.- Divide 55 by 32/5
55 / 1 / 32 /5 = (55 x 5) / (32 x 1)
= 275 / 32
2.- Convert 275/32 to a mixed fraction
8
32 275
256
19
Result 8 19/32 days
Part C
1.- Divide 55 by 7.25
50 / 7.25 = 5000 / 725
6
725 5000
- 4350
650
Result 6 650/750 = 6 26/29
The x-coordinate remains the same as the x-coordinate of point B.
The y-coordinate becomes the additive inverse of the y-coordinate of point B.
Answer: B. (3, -8)
Solving the given inequality for d, we get...
6d + 15 < 50
6d + 15-15 < 50-15 <<-- subtract 15 from both sides
6d < 35
6d/6 < 35/6 <<--- divide both sides by 6
d < 5.83
Which means that d can be any of the values in this set: {0, 1, 2, 3, 4, 5}
The smallest d can be is 0. In this scenario, Jeremy pays the $15 registration but doesn't rent the camera at all
The largest d can be is 5. In this scenario, Jeremy rents the camera for 5 days
Any larger value of d is not allowed as it would make the total cost go over $50
Notice how I'm rounding down regardless how close 5.83 is to 6
Answer:
16
Step-by-step explanation:
8x2
