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Nina [5.8K]
3 years ago
5

23 and 24 I need help please

Mathematics
1 answer:
Gnoma [55]3 years ago
5 0

Answer:

They should purchase the snack with the purple box. This is the answer for 23, i don't know what 24 is sorry.

Step-by-step explanation:

24÷3=8

8×5=40

so the first snacks would cost them $40.

then:

24÷4=6

6×6=36

so the second snacks would cost them $36

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tatuchka [14]
Can you take a picture of the tables so i can see my choices??
7 0
3 years ago
A sock drawer contains eight navy blue socks and five black socks with no other socks. If you reach in the drawer and take two s
Rzqust [24]

Answer:

a. the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b. the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c. the probability of either 2 navy socks is picked or one black  & one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

Step-by-step explanation:

A sock drawer contains 8 navy blue socks and 5 black socks with no other socks.

If you reach in the drawer and take two socks without looking and without replacement, what is the probability that:  

Solution:

total socks = N = 8 + 5 + 0 = 13

a) you will pick a navy sock and a black sock?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick the black sock, total number of socks left is 12.

Let B be the probability of picking a black sock again.

 P (B) = 5/12.

Then, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b) the colors of the two socks will match?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick another navy sock, total number of socks left is 12.

Let B be the probability of another navy sock again.

 P (B) = 7/12.

Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

Let D be the probability of picking a black socks first.

Then P (D) = 5/13

without replacing the black sock, will pick another black sock, total number of socks left is 12.

Let E be the probability of another black sock again.

 P (E) = 4/12.

Then, the probability of picking 2 black sock = P (D & E)

= (5/13 ) * (4/12) = 5/39 = 0.128

Now, the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c) at least one navy sock will be selected?

this means, is either you pick one navy sock and one black or two navy socks.

so, if you will pick a navy sock and a black sock, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

also, if you will pick 2 navy sock, Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

now either 2 navy socks is picked or one black  one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

4 0
3 years ago
The operation denoted is by * is commutative and why?​
kipiarov [429]

Answer:

The commutative property of multiplication states that changing the order of the numbers we are multiplying, does not change the product.

3 0
2 years ago
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IS THIS CORRECT PLEASE
IceJOKER [234]

Answer:

yes

Step-by-step explanation:

pic above

6 0
2 years ago
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Write each of the mixed numbers below as a fraction greater than one, and write each of the fractions greater
Softa [21]

Answer:

a. 13/3

b. 3 3/4

d. 1 7/8

c. 7/2

Step-by-step explanation:

a. 4 1/3 given

4*3=12 multiply the whole numbers with the denominator

12+1 =13 add the numerator to the product

13/3 put sum over denominator

b. 15/4 given

15/4=3 with a remainder of 3 divide numerator by denominator

3 3/4 rewrite as mixed number

d. 15/8 given

15/8=1 with a remainder of 7 divide numerator by denominator

1 7/8 rewrite as mixed number

c. 3 1/2 given

3*2=6 multiply whole number by denominator

6+1=7 add numerator to product

7/2 put sum over denominator

7 0
2 years ago
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