Answer:
The sum of 7 and x.
Step-by-step explanation:
PLS GIVE BRAINLIEST
Rewrite
log
(
2
x
)
=
4
log2x=4 in exponential form using the definition of a logarithm. If
x
x and
b
b are positive real numbers and
b
b
≠
≠
1
1, then
log
b
(
x
)
=
y
logbx=y is equivalent to
b
y
=
x
by=x.
10
4
=
2
x
Answer:
Step-by-step explanation:
Given equation is,
x² + (p + 1)x = 5 - 2p
x² + (p + 1)x - (5 - 2p) = 0
x² + (p + 1)x + (2p - 5) = 0
Properties for the roots of a quadratic equation,
1). Quadratic equation will have two real roots, discriminant will be greater than zero. [(b² - 4ac) > 0]
2). If the equation has exactly one root, discriminant will be zero [(b² - 4ac) = 0]
3). If equation has imaginary roots, discriminant will be less than zero [(b² - 4ac) < 0].
Discriminant of the given equation = 
For real roots,

p² + 2p + 1 - 8p + 20 > 0
p² - 6p + 21 > 0
For all real values of 'p', given equation will be greater than zero.
<u>Complete question:</u>
Refer the attached diagram
<u>Answer:</u>
In reference to the attached figure, (-∞, 2) is the value where (f-g) (x) negative.
<u>Step-by-step explanation:</u>
From the attached figure, it shows that given data:
f (x) = x – 3
g (x) = - 0.5 x
To Find: At what interval the value of (f-g) (x) negative
So, first we need to calculate the (f-g) (x)
(f – g ) (x) = f (x) – g (x) = x-3 - (- 0.5 x)
⇒ (f - g) (x) =1.5 x - 3
Now we are supposed to find the interval for which (f-g) (x) is negative.
⇒ (f - g) (x) = x - 3+ 0.5 x = 1.5 x – 3 < 0
⇒ 1.5 x – 3 < 0
⇒ 1.5 x < 3
⇒ 
⇒ x < 2
Thus for (f - g) (x) negative x must be less than 2. Thereby, the interval is (-∞, 2). Function is negative when graph line lies below the x - axis.
I'm pretty sure it is 4, 10.5/5 = 2.1 and 8.5/2.1 = 4.047619047619048 which to the nearest tenth is 4.0 or 4......hope this helps,and hope it is correct!!