All categories

2 years ago

What is the solution to the linear equation? 6k 10. 5 = 3k 12 k = 0. 5 k = 2 k = 7. 3 k = 9.

Mathematics

1 answer:

shtirl [24]2 years ago

3 0

The solution of the liner equation 6k + 10.5 = 3k + 12 is k = 1/2.

<h3>What is Linear Equation?</h3><h3>Linear equations are equations of the first order. The linear equations are defined for lines in the coordinate system. When the equation has a homogeneous variable of degree 1 (i.e. only one variable), then it is known as a linear equation in one variable.</h3>

Here, 6k + 10.5 = 3k + 12

6k - 3k = 12 - 10.5

3k = 1.5

k = 1.5/3

k = 1/2

Thus, The solution of the liner equation 6k + 10.5 = 3k + 12 is k = 1/2.

Learn more about Linear Equation from:

brainly.com/question/11897796

#SPJ1

You might be interested in

Between 1910 and 1930, what was the approximate increase in us homes with electricity

navik [9.2K]

nearly 68 percent of American homes were electrified. But, if you don't count farms, about 85 percent of Americans had electricity by the end of the 1920s.

And there's the rub. Rural communities, including farms, were far slower in adopting electricity than the rest of the country. Of the roughly 6.3 million American farms in 1922, only about 3% had electricity. It wasn't until 1935 that the U.S. government addressed this huge rural vs urban electric divide with the formation of the Rural Electrification Administration.

4 0

3 years ago

Read 2 more answers

Find 2 consecutive number whose product is 360

shtirl [24]

Answer:

This is impossible.

Step-by-step explanation:

There are no two consecutive numbers that their product is 360.

5 0

3 years ago

Choose the congruence theorem that you would use to prove the triangles congruent.

Evgesh-ka [11]

The answer is SSS . This is because the sides values are shown.

3 0

3 years ago

In a large midwestern university (the class of entering freshmen is 6000 or more students), an SRS of 100 entering freshmen in 1

Serga [27]

Answer:

The p-value of the test is 0.0228, which is less than the standard significance level of 0.05, which means that there is evidence that the proportion of freshmen who graduated in the bottom third of their high school class in 2001 has been reduced.

Step-by-step explanation:

Before solving this question, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

1999:

20 out of 100 in the bottom third, so:

$p_1 = \frac{20}{100} = 0.2$

$s_1 = \sqrt{\frac{0.2*0.8}{100}} = 0.04$

2001:

10 out of 100 in the bottom third, so:

$p_2 = \frac{10}{100} = 0.1$

$s_2 = \sqrt{\frac{0.1*0.9}{100}} = 0.03$

Test if proportion of freshmen who graduated in the bottom third of their high school class in 2001 has been reduced.

At the null hypothesis, we test if the proportion is still the same, that is, the subtraction of the proportions in 1999 and 2001 is 0, so:

$H_0: p_1 - p_2 = 0$

At the alternative hypothesis, we test if the proportion has been reduced, that is, the subtraction of the proportion in 1999 by the proportion in 2001 is positive. So:

$H_1: p_1 - p_2 > 0$