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8_murik_8 [283]
4 years ago
9

I actually need help bhっっっっb

Mathematics
1 answer:
Artyom0805 [142]4 years ago
5 0

How long have you been stuck on this problem???

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Simplify the expression. Write answer using only positive exponents.<br><br><br> (1/3a^3)^-4
Artemon [7]

Answer:

81/a^12

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
&lt;1 and &lt;2 form a linear pair. The measure of &lt;2 is six more than twice the measure of &lt;1. Find the measure of &lt;2
MrMuchimi

Answer:

122 Degrees

Step-by-step explanation:

Since we are given that angle 1 and 2 make a linear pair:

angle 1 + angle 2 = 180 degrees ----------------------------(1)

We have also been told that angle 2 is 6 more than twice the measure of angle 1

Which means: angle 2 = (2*angle1)  + 6 -------------------(2)

From putting the value of angle 2 in (1) from (2)

<em>angle 1 + 2*angle 1 + 6 = 180</em>

<em>3*angle 1 = 174</em>

angle 1 = 58 degrees -----------------------(3)

From (1) and (3):

<em>angle 2 + 58 = 180</em>

angle 2  = 122 degrees

Therefore, the measure of angle 2 is 122 degrees

7 0
4 years ago
Suppose that the mean water hardness of lakes in Kansas is 425 mg/L and these values tend to follow a normal distribution. A lim
tino4ka555 [31]

Answer:

The mean water hardness of lakes in Kansas is 425 mg/L or greater.

Step-by-step explanation:

We are given the following data set:

346, 496, 352, 378, 315, 420, 485, 446, 479, 422, 494, 289, 436, 516, 615, 491, 360, 385, 500, 558, 381, 303, 434, 562, 496

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{10959}{25} =438.36

Sum of squares of differences = 175413.76

S.D = \sqrt{\dfrac{175413.76}{24}} = 85.49

Population mean, μ = 425 mg/L

Sample mean, \bar{x} = 438.36

Sample size, n = 25

Alpha, α = 0.05

Sample standard deviation, s = 85.49

First, we design the null and the alternate hypothesis

H_{0}: \mu \geq 425\text{ mg per Litre}\\H_A: \mu < 425\text{ mg per Litre}

We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{438.36 - 425}{\frac{85.49}{\sqrt{25}} } = 0.7813

Now, t_{critical} \text{ at 0.05 level of significance, 24 degree of freedom } = -1.7108

Since,                        

The calculated t-statistic is greater than the critical value, we fail to reject the null hypothesis and accept it.

Thus, the mean water hardness of lakes in Kansas is 425 mg/L or greater.

6 0
3 years ago
The table shows information about the numbers of hours 30 children spent on their tablets one evening.A) Find the class interval
Tresset [83]

Answer:

A- 2<h<3   B- 2.2

Step-by-step explanation:

 when you make a dot plot, the median is 11. using that dot plot, you can approximate a mean to be around 2

8 0
3 years ago
What is the volume of the prism below?
expeople1 [14]

the exact exact answer would be a decimal, but if you round it it will be c

hope this helps

Step-by-step explanation:

7 0
3 years ago
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