An ordered pair which makes both inequalities true is (-1, -3).
<h3>What is an ordered pair?</h3>
An ordered pair is a pair of two points that are commonly written in a fixed order within parentheses as (x, y), which represents the x-coordinate or x-axis (abscissa) and the y-coordinate or y-axis (ordinate) on the coordinate plane of any graph.
Next, we would test the ordered pair with the given system of inequalities in order to determine which is true.
For ordered pair (-3, 5), we have:
y < –x + 1
5 < -(-3) + 1
5 < 3 + 1
5 < 4 (False).
For ordered pair (-2, 2), we have:
y < –x + 1
2 < -(-2) + 1
2 < 2 + 1
2 < 3 (True).
y > x
2 > -2 (True)
For ordered pair (-1, -3), we have:
y < –x + 1
-3 < -(-1) + 1
-3 < 1 + 1
-3 < 2 (True).
y > x
-3 > -1 (False)
For ordered pair (0, -1), we have:
y < –x + 1
-(-1) < -(0) + 1
1 < 1
1 < 1 (False).
y > x
-1 > 0 (False)
Read more on inequality here: brainly.com/question/27166555
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Answer:
One solution: (2.5,0)
Step-by-step explanation:
We can use substitution for the solution. Substitute y=2x-5 to -8x-4y=-20 so that you end up with -8x-8x+20=-20. Next you want to add like terms which will be -16x+20=-20, next you want isolate x by subtracting 20 from both sides and leaves you with -16x=-40. Divide -16 on both sides to fully isolate x and will leave you with x=2.5. Now substiture in 2.5 for x in y=2x-5 to get y=2(2.5)-5 which will then lead to y=0.
Step-by-step explanation:
number2 the answer is a and
number 3 the answer is letter b
So use cancelation
multiply first equation by 2
2x+8y=10
times 2
4x+16y=20
now add
4x+16y=20
<u>-4x-9y=-13 +
</u>0x+7y=7
7y=7
divide by 7
y=1
subsittue
2x+8y=10
2x+8(1)=10
2x+8=10
subtract 8 from both sides
2x=2
divide by 2
x=1
x=1
y=1
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