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IceJOKER [234]
4 years ago
9

Please answer correctly thank you!

Mathematics
1 answer:
Nina [5.8K]4 years ago
5 0

If you rotate the triangle so that the 6 is on the bottom, the two sides are both 6.2.

Because the two sides are equal the two angles at the bottom would also be equal. One is given as 61 degrees, so the other bottom angle is also 61 degrees.

The three inside angles of a triangle need to equal 180, so X would equal 180 minus the two bottom angles.

X = 180 - 61 - 61 = 58 degrees.

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Find the missing side lengths. leave your answers as radicals in simplest form.
Murrr4er [49]

Answer:

x = 4 , y = 2

Step-by-step explanation:

Using the sine / tangent ratios in the right triangle and the exact values

sin60° = \frac{\sqrt{3} }{2} and tan60° = \sqrt{3} , then

sin60° = \frac{opposite}{hypotenuse} = \frac{2\sqrt{3} }{x} = \frac{\sqrt{3} }{2} ( cross- multiply )

x \sqrt{3} = 4\sqrt{3} ( divide both sides by \sqrt{3} )

x = 4

and

tan60° = \frac{opposite}{adjacent} = \frac{2\sqrt{3} }{y} = \sqrt{3} ( multiply both sides by y )

y \sqrt{3} = 2\sqrt{3} ( divide both sides by \sqrt{3} )

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3 years ago
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Write the number in expanded 280.34
BARSIC [14]

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Step-by-step explanation:

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3 years ago
Read 2 more answers
I DON’T UNDERSTAND! PLEASE HELP!
Brums [2.3K]

Answer:

The height of the water is 60.5\ ft

Step-by-step explanation:

step 1

Find the volume of the tank

The volume of the inverted right circular cone is equal to

V=\frac{1}{3}\pi R^{2} H

we have

R=16\ ft

H=96\ ft

substitute

V=\frac{1}{3}\pi (16)^{2} (96)

V=8,192\pi\ ft^{3}

step 2

Find the 25% of the tank’s capacity  

V=(0.25)*8,192\pi=2,048\pi\ ft^{3}

step 3

Find the height, of the water in the tank  

Let

h ----> the height of the water  

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional

\frac{R}{H}=\frac{r}{h}

substitute

\frac{16}{96}=\frac{r}{h}\\ \\r= \frac{h}{6}

where

r is the radius of the smaller cone of the figure

h is the height of the smaller cone of the figure

R is the radius of the circular base of tank

H is the height of the tank

we  have

V=2,048\pi\ ft^{3} -----> volume of the smaller cone

substitute

2,048\pi=\frac{1}{3}\pi (\frac{h}{6})^{2}h

Simplify

221,184=h^{3}

h=60.5\ ft

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3 years ago
What is the value of the expression when a = 4, b = 3 , and c = 10?
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C it’s wrong so don’t listen to me
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