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2 years ago

Sherl gives her dog groomer a generous tip. Using a

Mathematics

1 answer:

anzhelika [568]2 years ago

4 0

Answer:

Step-by-step explanation:

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adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the

Zigmanuir [339]

Answer:

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$ and $\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

Step-by-step explanation:

The equation of the isotope decay is:

$\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }$

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

$\tau = \frac{5568\,years}{\ln 2}$

$\tau \approx 8032.926\,years$

The decay time is:

$t = 1315\,years + 2007\,years \pm 13\,years$ (There is no a year 0 in chronology).

$t = 3335 \pm 13\,years$

Lastly, the relative amount is estimated by direct substitution:

$\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$

$\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

4 0

2 years ago

Answer this question

Katen [24]

Step-by-step explanation:

It is (A)95° by using External Angle Property of triangles.

BTW whats up with that order C-D-B-A

8 0

3 years ago

The graphs of y-2x = 1, 4x + y = 7, and 2y - x= -4 contain the sides of triangle. Find the coordinates of the vertices of the tr

Darina [25.2K]

Answer:

i think the right answer is b

6 0

3 years ago

Can people help? When a grizzly bear hibernates, its heart rate drops to

avanturin [10]

Like you said: 10 beats per minute, which is 20% percent of its normal value.

So: 10 per minute is 20% of the normal rate. You will divide each side by 0.2, which will result in 50 per min

8 0

2 years ago

How do you do this? Thanks for your time and effort! Plz help:)))))) THANKSSSSS

Nitella [24]

R=-1/800(x^2-2400x)
use R'=0
R'=1/400x-300, 1/400x=300 => x=1200 critical point
take R(1200), we know its max bcuz of the orientation of R

4 0

3 years ago