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dalvyx [7]
3 years ago
11

A horizontal line means the object is moving at a __________ speed.

Physics
2 answers:
MariettaO [177]3 years ago
8 0
A horizontal line means the object is. moving at a constant speed.
vfiekz [6]3 years ago
4 0

Answer:

<u>Uniform</u>

Explanation:

Pls mark as Brainliest answer!!

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Please help asap!!!!!!!!!!!
Tomtit [17]
The answer would be 20000

The answer in standard form/scientific notation would be 2 x 10^4

(The exponent is 4 because that's how many digits after the 2 there is)
8 0
2 years ago
Kate, a bungee jumper, wants to jump off the edge of a bridge that spans a river below. Kate has a mass m, and the surface of th
MArishka [77]

Answer:

1)   d = h- L - mg / k , 2)        k = 2 mg/h    (-1 +2 L / h)

Explanation:

1) Let's use the translational equilibrium equation

       F_{e} -W = 0

       F_{e} = W

       k x = mg

       x = mg / k

         

from the statement of the exercise the height of the bridge, for the reference system in the river, is

        h = L + x + d

        x = h - L - d

we substitute

        h - L -d = mg / k

        d = h- L - mg / k

2) They ask us for the spring constant. For this part we can use energy conservation

Starting point. At the point before jumping

        Em₀ = U = m g h

Final Point. When it's hanging

        Em_f =   K_{e} + U = ½ k x² + mg d

        Em₀ = Em_f

         mg h = 1 / k x² + m g d

in the exercise they indicate that Kate touches the surface of the river, so the distance d = 0

         mg h = ½ k x²

         k = 2 mg h / x²

       

we substitute the value of x

        k = 2mg  h / (h -L)²

        k = 2mg  h / (- L + h)²

we simplify the expression

       k = 2mg  h / [h² (1- L / h)²]

       k = 2m /h      (1- L / h)⁻²

In these jumps the bridge height is always greater than the length of the rope L / h <1, so we can expand the last expression

          (1- L / h)⁻² = 1 - 2 (1 -L / h) + 2 3/2!   (1 -L / h)² + ...

for simplicity let's keep up to the linear term, we substitute in the solution

       k = 2 mg/h    [1 - 2 (1- L / h)]

       k = 2 mg/h    (-1 +2 L / h)

     

8 0
3 years ago
The amount of matter I’m an object is know as
Oduvanchick [21]

The amount of matter I’m an object is know as <em>the object's mass</em> .

8 0
4 years ago
A hockey puck is hit so that it leaves the stick at 50.4m/s. If it takes 0.25 s for the puck to hit the boards, how far is the p
notka56 [123]
Speed = 50.4 m/s
Time = 0.25 s

Distance  =  (speed) x (time)  =  (50.4 m/s) x (0.25 s)  =  12.6 meters.
3 0
3 years ago
Ne W2
levacccp [35]

Answer:

3.82746e+26 watts

Explanation:

There are two ways to solve this problem. One way is to use the equation

L = 4πσR²T⁴

where

L = the sun's bolometric (all-spectrum) luminous power

σ = 5.670374419e-8 W m⁻² K⁻⁴ = the Stefan-Boltzmann constant

R = 6.957e+8 meters = the sun's radius

T = 5771.8 K = the sun's effective temperature

You find that

L = 3.82746e+26 watts

The other way to solve the problem is to use the Planck integral for radiant flux.

L = 4π²R ∫(v₁,v₂) 2hv³/{c² exp[hv/(kT)]−1} dv

where

h = 6.62607015e-34 J sec

c = 299792458 m sec⁻¹

k = 1.380649e-23 J K⁻¹

v₁ = 0 = frequency band lower bound, in Hz

v₂ = ∞ = frequency band upper bound, in Hz

You find, once again, that

L = 3.82746e+26 watts

The advantage of using the Planck integral becomes clear when you want to calculate the sun's luminous power only in a specific band, rather than across the entire spectrum. For example, if we do the calculation again, except that we use

v₁ = 4.1e+14 = frequency band lower bound, in Hz

v₂ = 7.7e+14 Hz = frequency band upper bound, in Hz

restricting ourselves to the visible spectrum. We find that

L (visible) = 1.56799e+26 watts

So the fraction of the sun's luminosity that is in the visible spectrum is

L (visible) / L = 0.4096686

5 0
4 years ago
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