Answer:
Explanation:
Given two vectors as follows
E₁ = 13.5 i -12 j
E₂ = -7.4 i - 4.7 j
Resultant E = E₁ + E₂
= 13.5 i -12 j -7.4 i - 4.7 j
E = 6.1 i - 16.7 j
a ) X component of resultant = 6.1 N
b ) y component of resultant = -16.7 N
Magnitude of resultant = √ ( 6.1² + 16.7² )
= 17.75 N
d ) If θ be the required angle
tanθ = 16.7 / 6.1 = 2.73
θ = 70° .
counterclockwise = 360 - 70 = 290°
Answer:
T = 365.58 K
Explanation:
Given that,
The concentration of solution, C = 0.750M
Osmotic pressure, P = 22.5 atm
We need to find the temperature of the solution.
The formula for the osmotic pressure is given by :
![P=CRT](https://tex.z-dn.net/?f=P%3DCRT)
Where
R is gas constant, ![R=0.08206\ L\ atm/mol-K](https://tex.z-dn.net/?f=R%3D0.08206%5C%20L%5C%20atm%2Fmol-K)
![T=\dfrac{P}{CR}\\\\=\dfrac{22.5}{0.75\times 0.08206}\\\\=365.58\ K](https://tex.z-dn.net/?f=T%3D%5Cdfrac%7BP%7D%7BCR%7D%5C%5C%5C%5C%3D%5Cdfrac%7B22.5%7D%7B0.75%5Ctimes%200.08206%7D%5C%5C%5C%5C%3D365.58%5C%20K)
So, the temperature of the solution is 365.58 K.
Gases are more compressible than liquids.
Answer:
v0 = 24.42 m/s (Approx)
Explanation:
Given:
Increase in frequency = 7.1% =
Computation:
Assume n = 100%
n1 = [(v+v0)/(v+v1)]n
[100 + 7.1] = [(344+v0)/(344+0)]100
107.1 = [(344+v0)/(344)]100
v0 = 24.42 m/s (Approx)
Answer:
ΔEP = -1.36 J
Explanation:
Given:
- The complete question is as follows:
" A mass of 0.105 kg hangs from a vertical spring in the lab room. You pull down on the mass and throw it vertically downward. The speed of the mass just after leaving your hand is 5.20 m/s.
"
Find:
When the mass has moved downward a distance of 0.04 m, the speed of the mass has decreased to 1.39 m/s.
Solution:
- The initial velocity of the system vi = 5.20 m/s
- The mass m = 0.105 kg
- The final velocity of mass vf = 1.39 m/s
- Change in distance d = 0.04m
Solution:
- When the mass (m) is moved down by (d) the work-done by gravity P.E translates to change in kinetic energy K.E and elastic potential energy of the spring EP . The energy balance can be set as:
ΔEP + P.E = ΔK.E
ΔEP + m*g*h = 0.5*m*(vf^2-vi^2)
ΔEP = 0.5*m*(vf^2-vi^2) - m*g*h
ΔEP = 0.105* (- 9.81*0.04 + 0.5*(1.39^2-5.2^2) )
ΔEP = - 1.36 J
- Since, The work done by spring is negative because the displacement is downwards and the force is upwards.