<span>You can start with the equations you know
a=v^2/r = (2pi*r/T)^2/r = 4pi^2r/T^2
Radius of earth (R) = 6378.1 km
Time in one day (T) = 86400 seconds
Latitude = 44.4 degrees
If you draw a circle and have the radius going out at a 44.4 degree angle above the center you can then find the r.
r=Rcos(44.4)
r=6378.1cos(44.4)
r= 4556.978198 km or 4556978 m
Now you can plug this value into the acceleration equation from above...
a= 1.8*10^8/7.47*10^9
a= .0241 m/s^2 </span>
Answer:
Explanation:
From the given information:
the car's momentum = momentum of the truck
∴
(a) 816 kg × v = 2650 kg × 16.0 km/h
v = (2650 kg × 16.0 km/h) / 816 kg
v = 51.96 km/hr
(b) 816 kg × v = 9080 kg × 16.0 km/h
v = (9080 kg × 16.0 km/h) / 816 kg
v = 178.04 km/hr
Answer:
The correct answer is 24.
Explanation:
Answer:
The velocity of a ball will be "-70.13 m/s".
Explanation:
The given values are:
u = 70 m
t = 0.0 s
g = a = -9.8 m/s²
s = -1 m
v = ?
As we know,
The equation of motion will be:
⇒ 
On substituting the estimated values, we get
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
In downward direction, it will be:
⇒ 
