Answer: Ribosomes are the site of protein synthesis, and they convert the coded information in messenger RNA into an actual protein molecule.
I hope this helped! OvO
Answer:
1 m
Explanation:
Given that
Mass of the child, m = 15 kg
Distance of the pivot, d = 1.5 m
Force applied, F = 220 N
To solve this problem, we first need to find the torque around the pivot.
Torque, t = mgd, where
m is the mass of the child
g is the acceleration due to gravity and
d is the distance of the pivot.
Thus, we can say that the torque is
T = 15 * 9.8 * 1.5
T = 220.5 Nm
This torque we have gotten would be used to find the distance, using the inverse of the equation.
T = F * d
d = T / F
d = 220.5 / 220
d = 1 m
Therefore, the minimum distance on the other side of the pivot required is 1 m
Answer:
I believe the answer is C. 0.3m/s/s
Explanation:
hope this helps :) lemme know if I'm correct
That depends on how much of it you have, but it's a hugely enormous gigantic number in even the smallest sample.
You can see from the formula that there are 12 atoms in every molecule of the stuff !
Answer:
The uncertainty in the volume of the sphere is ![1.059\times 10^{4} m^{3}](https://tex.z-dn.net/?f=1.059%5Ctimes%2010%5E%7B4%7D%20m%5E%7B3%7D)
Solution:
As per the question:
Measured radius of the sphere, R = 135.4 m
Uncertainty in the radius, ![\Delta R = 4.6 cm = 4.6\times 10^{- 2} = 0.046 m](https://tex.z-dn.net/?f=%5CDelta%20R%20%3D%204.6%20cm%20%3D%204.6%5Ctimes%2010%5E%7B-%202%7D%20%3D%200.046%20m)
We know the volume of the sphere is:
![V_{s} = \frac{4}{3}\pi R^{3}](https://tex.z-dn.net/?f=V_%7Bs%7D%20%3D%20%5Cfrac%7B4%7D%7B3%7D%5Cpi%20R%5E%7B3%7D)
We know that the fractional error for the given sphere is given by:
![\frac{\Delta V_{s}}{V_{s}} = \frac{4}{3}\pi.\frac{|Delta R}{R}](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20V_%7Bs%7D%7D%7BV_%7Bs%7D%7D%20%3D%20%5Cfrac%7B4%7D%7B3%7D%5Cpi.%5Cfrac%7B%7CDelta%20R%7D%7BR%7D)
where
= uncertainty in volume of sphere
Now,
![\Delta V_{s} = \frac{4}{3}\pi 3R^{2}\Delta R](https://tex.z-dn.net/?f=%5CDelta%20V_%7Bs%7D%20%3D%20%5Cfrac%7B4%7D%7B3%7D%5Cpi%203R%5E%7B2%7D%5CDelta%20R)
Now, substituting the suitable values:
![\Delta V_{s} = 4\pi (135.4)^{2}\times 0.046 = 1.059\times 10^{4} m^{3}](https://tex.z-dn.net/?f=%5CDelta%20V_%7Bs%7D%20%3D%204%5Cpi%20%28135.4%29%5E%7B2%7D%5Ctimes%200.046%20%3D%201.059%5Ctimes%2010%5E%7B4%7D%20m%5E%7B3%7D)