The mass of an object can neither be change but the weight of the object can be changed.
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What causes a decrease in an object weight?</h3>
The weight of the body or of an object can be changed if the body is placed farther away from the earth or placed in the planet which is far away from the earth's gravitational field, so the force of gravity on the object will change. However the mass of the body or mass of the object will remains the same regardless of whether the object is on Earth, in outer space, or on the Moon. By doing so the weight of the object or body will change but the mass remains the same.
So we can conclude that: The mass of an object can neither be change but the weight of the object can be changed.
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Answer:
If a vertical line extending down from an object's CG extends outside its area of support, the object will topple
Explanation:
We can understand better this situation using a diagram with the forces acting on it.
In the attached image we can see that when the gravity center is bouncing outside from the area of the pedestal, the object will be out of balance and will fall.
Answer:
120 volts is the root mean square (rms) average of the voltage as it varies with time.
Explanation:
A. The average voltage over many weeks of time (false)
Reason: Average AC voltage over one cycle is cycle (from one peak to other) is zero and so over many weeks of time it is zero.
B. The peak voltage from an AC wall receptacle (false)
Reason: The peak voltage of an AC source in North America is zero.
C. The arithmetic mean of the voltage as it varies with time (false)
Reason: Arithmetic mean AC voltage over one cycle is cycle (from one peak to other) is zero and so over many weeks of time it is zero.
D. One-half the peak voltage (false)
Peak voltage =170 Volts
One-half the peak voltage = 85 volts
E. The root mean square (rms) average of the voltage as it varies with time (True)
Reason:
The peak voltage and root mean square voltage are related by:

Average value of voltage over one cycle is zero, so instead of calculating average voltage for AC peak voltage is first squared and the mean is calculated.
110 grams
mass of salt + mass of water
10 + 100
110g
Answer:
Explanation:
Given that:
Charge Q = 10400 C
current I = 0.530 mA
From our previous knowledge, we know that charge Q can be expressed as:
Q = I×t
where
I = current and t = time
∴
replacing our values
10400 = (0.530×10⁻³) t
t = 10400/(0.530×10⁻³)
t = 19622641.51 seconds
However, the required flow of electrons per seconds can be calculated by using the formula:
number of electrons/second = current (I)/ charge on electron
= (0.530×10⁻³)/(1.6×10⁻¹⁹)
= 3.3125×10¹⁵ electrons