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sveta [45]
3 years ago
5

Please help!! Quickly

Mathematics
1 answer:
irina [24]3 years ago
7 0

Answer:

The answer to your question is: a = 3.5 units

Step-by-step explanation:

Right triangle

to find a we need to use the trigonometric function cosine

cosine Ф = opposite leg / hypothenemus

Clear opposite leg from the equation

opposite leg = hypothenemus x cosine Ф

a = opposite leg = 5 x cosine 45

a = 5 x 0.70

a = 3.5 units

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Jenna has bought a new hybrid car. Each week for a period of seven weeks, she has noted the fuel efficiency (in miles per gallon
Leviafan [203]

Answer: 0.82 miles per gallon

Step-by-step explanation:

Given : Jenna has bought a new hybrid car. Each week for a period of seven weeks, she has noted the fuel efficiency (x) (in miles per gallon) of her car.

The results are :45 44 43 44 45 44 43

The formula to find the standard deviation is given by :-

\sigma=\sqrt{\dfrac{\sum_{i=1}^n(x_i-\overline{x})^2}{n-1}}

First we find mean of the given data ,

\overline{x}=\dfrac{\sum^n_{i=1}x_i}{n}\\\\=\dfrac{45+44+43+44+45+44+43}{7}=\dfrac{308}{7}=44

Now,

{\sum_{i=1}^n(x_i-\overline{x})^2=(1)^2+(0)^2+(-1)^2+(0)^2+(1)^2+(0)^2+(-1)^2

=1+1+1+1=4

Now,  standard deviation of the above results will be :-

\sigma=\sqrt{\dfrac{4}{7-1}}\\\\=\sqrt{\dfrac{4}{6}}\\\\=\dfrac{2}{\sqrt{3}}=0.816496580928\approx0.82

Hence, the standard deviation of these results = 0.82 miles per gallon

8 0
4 years ago
Determine the zeros of the function <br> 5) y=-x² + 2x + 1
Rus_ich [418]
<h3>Zeros of function are x = 1 + \sqrt{2} \text{ and } x = 1 - \sqrt{2}</h3>

<em><u>Solution:</u></em>

<em><u>We have to find the zeros of the function</u></em>

y = -x^2 + 2x+1

Find the zeros of function:

-x^2 + 2x+1 = 0\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-1,\:b=2,\:c=1\\\\x  =\frac{-2\pm \sqrt{2^2-4\left(-1\right)1}}{2\left(-1\right)}

Simplify\\\\x=\frac{-2 \pm \sqrt{4+4}}{-2}\\\\x =\frac{-2 \pm \sqrt{8}}{-2}\\\\Simplify\\\\x =\frac{-2 \pm 2 \sqrt{2}}{-2}\\\\x = 1 \pm \sqrt{2}

We have two zeros

x = 1 + \sqrt{2} \text{ and } x = 1 - \sqrt{2}

Thus zeros of function are x = 1 + \sqrt{2} \text{ and } x = 1 - \sqrt{2}

3 0
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Step-by-step explanation:

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