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BigorU [14]
3 years ago
7

Help math is not my subject

Mathematics
2 answers:
Mashutka [201]3 years ago
6 0
First you would do 3-9 which is -6 then -4-1 which is -5 then since the parenthesis are close to each other you would multiply and you should get

30 
Pepsi [2]3 years ago
6 0
(3 - 9)(-4 - 1)

Order of operations =  PEMDAS
P = Parentheses 
E = Exponents 
M = Multiplication 
D = Division
A = Addition
S = Subtraction 

(3 - 9)(-4 - 1)
(-6)(-4 - 1)
(-6)(-5)
30

(3-9)(-4 - 1) = 30
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Solve for x<br>x/6=2<br><br>x=3<br>X=-12<br>X=12<br>Please help need fast
Alborosie

Answer:

Its answer is 12 simple

4 0
3 years ago
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What are the coordinates of the vertices of the pre-image given? ry= −x ◦ T1, −2(x, y) 
nataly862011 [7]
<h3><u>Answer:</u></h3>

Hence, the coordinates of pre-image are:

A(1,6) , B(0,4) , C(3,4) , D(2,6)

<h3><u>Step-by-step explanation:</u></h3>

We have to find the  coordinates of the vertices of the pre-image given?

Ry= −x ◦ T_1, −2(x, y)

i.e. we have to find the composition of reflection along the line y=-x and translation with the rule:

(x,y) → (x+1,y-2)

Now we have coordinates of A",B",C" and D" as:

A"(-4,-2)

B"(-2,-1)

C"(-2,-4)

D"(-4,-3)

Now we are asked to find the coordinates of the pre-image.

Also when any point is reflected along y=-x then the point is transformed to:

(x,y) → (-y,-x)

Let A,B,C and D are the points of the pre-image.

Hence, the coordinates of the pre-image are given as:

so, the transformation is given as:

A→A'→A"

B→B'→B"

C→C'→C"

D→D'→D"

Where A',B',C',D' represents the transformation after translation and A",B",C",D" represents the transformation after reflection as well.

The coordinates of A' are (2,4)

B' are (1,2)

C' are (4,2)

and D' are (3,4)

Now, the coordinates of pre-image are given as:

A'(x,y)  → A(x-1,y+2)=A(1,6)

B'(x,y)  → B(x-1,y+2)=B(0,4)

C'(x,y)  → C(x-1,y+2)=C(3,4)

and D'(x,y)  → D(x-1,y+2)=D(2,6)

Hence, the coordinates of pre-image are:

A(1,6) , B(0,4) , C(3,4) , D(2,6)

4 0
3 years ago
Pls help algebra 2 mmmmmm
Tom [10]

Answer:

497

Step-by-step explanation:

hehe trust me

5 0
3 years ago
The sum of 2 consecutive integers is one less than 3 times the smaller integer find the 2 integers
aalyn [17]

The two consecutive integers are 2 and 3

<em><u>Solution:</u></em>

Let x and x + 1 are the two consecutive integers

Let "x" be the smallest integer

Let "x + 1" be the larger integer

<em><u>Given that, sum of 2 consecutive integers is one less than 3 times the smaller integer</u></em>

Therefore,

sum of 2 consecutive integers = one less than 3 times the smaller integer

sum of 2 consecutive integers = 3 times the smaller integer - 1

x + x + 1 = 3(x) - 1

2x + 1 = 3x - 1

3x - 2x = 1 + 1

x = 2

Thus the smaller integer = x = 2

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Thus the two consecutive integers are 2 and 3

5 0
4 years ago
Find f(3) given f(x)=4^x
lions [1.4K]

Answer:

f(3) , x is 3.

4^3

4(4) = 16

16(4) = 64

4^3 = 64

f(3) = 64

6 0
3 years ago
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