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Alik [6]
3 years ago
15

Please help ASAP please

Mathematics
2 answers:
mihalych1998 [28]3 years ago
6 0

do you some help ?, I can try my best to help

gulaghasi [49]3 years ago
4 0
I think the points are T= -2,1 Q= 1,3 R=3,-3 S= 0,-3 x, y
You might be interested in
Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective
soldier1979 [14.2K]

Answer:

a) P[C]=p^n

b) P[M]=p^{8n}(9-8p^n)

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

P[C]=p^n

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)

c)

P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

6 0
3 years ago
+ ES player
Maslowich

Answer:

the answer is B

Step-by-step explanation:

$8 per day

$6 per walk

walk(w)

8+6w

7 0
3 years ago
In Megan's class, 4/7 of the students are girls. Of the girls, 2/3 participate in sports. What fraction of Megan's class are gir
andreev551 [17]

Answer:

Step-by-step explanation:

X = the number of students in Megan's class

4/7 X = the number of girls in the class (G)

4/7 * 2/3 = the number of girls in the class who participate in sports

4/7 * 2/3 = 8/21 of girls in Megan's class participate in sports

4 0
3 years ago
Help me please I need assistance!​
olganol [36]

Answer:

84ft

Step-by-step explanation:

one side of the house is 14 units

since 1unit=6ft

Length of one side of her house= 14(6)=84ft

7 0
3 years ago
Hi help plz i need like now​
Mazyrski [523]

Answer:

y=1/2x+5

Step-by-step explanation:

  • standard form: y-0=1/2(x- -10)                *(x- -10) = (x+10)
  • y=1/2x+5 which is now in slope-intercept

4 0
3 years ago
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