2 years ago

Help pls ill give brainliest

Mathematics

1 answer:

Degger [83]2 years ago

8 0

X > two is the right answer

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In a class of 40 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose

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Step-by-step explanation:

Given

There are total 40 students in a class

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No of students with Pierced ear n(E)=36

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$n\left ( N\cup E\right )=n\left ( E\right )+n\left ( N\right )-n\left ( N\cap E\right )$

where $n\left ( N\cup E\right )=$ Students either nose or ear Pierced

$n\left ( N\cap E\right )=$ no of students having both nose and ear pierced

$40=7+36-n\left ( N\cap E\right )$

$n\left ( N\cap E\right )=43-40=3$

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3 years ago

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