Answer:
The slope of the line is -3.
Step-by-step explanation:
The slope equation is:
m= y2-y1/x2-x1
In this case:
m= -3-6/2+1 (remember that a negative minus a negative gives you a positive)
Which equals:
m=-9/3
Divide and you get -3.
Answer:
Jaw saw an average of 6 birds each day
Step-by-step explanation:
Given: One day, Jean saw 7 birds. The next day, she saw 11 birds. The next day, she saw no birds.
To find: average number of birds Jean saw each day
Solution:
Average is a central value of a set of terms.
Average of terms
is given by 
Number of birds, Jean saw on day one
= 7
Number of birds, Jean saw on the second one
= 7
Number of birds, Jean saw on the third one
= 7
So,
average number of birds Jean saw each day = 
Therefore,
Jaw saw an average of 6 birds each day
Answer: The starting time is 2:27 and finishing time is 7:09.
Step-by-step explanation: It is given that Ben started from 4th street and he finished at 98th street.
Also, at 3:00, he was on 15th street and at 4:30, he was on 45th street.
That is, time taken to cover (45-15), i.e., 30 streets is 90 minutes, so the time taken to cover 1 street is 3 minutes.
Therefore, Ben covers distance from one street to second in 3 minutes. Since he started from 4th street, and there are 11 streets to cover between 4 and 15, so Ben's starting time was (3:00 - 3×11 min) = 2:27.
And his finishing time was (4:30 + 3×53 min) = 7:09.
Again, the equation that tells us on what street 'N' he was after time 'T' of his starting can be written as

Thus, the starting and finishing time was 2:27 and 7:09 respectively.
If it is 50% then it should be half of the original price.
For Example: $30.00 - 50%... the answer would be $15.00 since its the half of the $30.00
Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer