On the sheet, it's not even asking you for the dimensions.
It's just asking you to set up the <em>equation that you would use</em>
to find the dimensions. That's a great way to do it, because
nobody actually needs the answers, the whole thing is only
meant to help you learn HOW to find them.
==========================================
Call the width of the window 'W' .
We know that the length is 5 feet more than the width, so the length is (W + 5).
The area is (length times width).
Area = (W + 5) times (W).
36 = (W + 5) W
36 = W² + 5W
Subtract 36 from each side:
W² + 5W - 36 = 0
That's choice-4 .
Answer:
a

b
![x(t) = x_o e^{\frac{-\alpha y_o }{\beta }[e^{-\beta t} - 1] }](https://tex.z-dn.net/?f=x%28t%29%20%3D%20%20x_o%20e%5E%7B%5Cfrac%7B-%5Calpha%20y_o%20%7D%7B%5Cbeta%20%7D%5Be%5E%7B-%5Cbeta%20t%7D%20-%201%5D%20%7D)
c

Step-by-step explanation:
From the question we are told that

Now integrating both sides

Now taking the exponent of both sides

=> 
Let 
So

Now from the question we are told that

Hence

=> 
So

From the question we are told that

substituting for y

=> 
Now integrating both sides

Now taking the exponent of both sides

=> 
Let 
=> 
Now from the question we are told that

So

=> 
divide both side by 
=> 
So

=> 
=> ![x(t) = x_o e^{\frac{\alpha y_o }{\beta }[e^{-\beta t} - 1] }](https://tex.z-dn.net/?f=x%28t%29%20%3D%20%20x_o%20e%5E%7B%5Cfrac%7B%5Calpha%20y_o%20%7D%7B%5Cbeta%20%7D%5Be%5E%7B-%5Cbeta%20t%7D%20-%201%5D%20%7D)
Generally as t tends to infinity ,
tends to zero
so

(

)we need 3 equations
1. midpoint equation which is (

) when you have 2 points
2. distance formula which is D=

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height
so
x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=(

)
midpoint=(

)
midpoint= (15,8)
point x=(15,8)
y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=(

)
midpoint=(

)
midpoint=(13,4)
Y=(13,4)
legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D=

D=

D=

D=

D=

BC=

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D=

D=

D=

D=

D=

XY=

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC=

and XY=

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D=

D=

D=

D=

D=

AD=

so we have
AD=

BC=
XY=

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
(

) times 1/2 times

=
(

) times \sqrt{5} [/tex] =

=

=80

=252.982
X=(15,8)
Y=(13,4)
BC=

XY=

Area=80

square unit or 252.982 square units
Base x height divided by 2
10x8=80
80÷2=40
area=40
4/7 to a percent is about 57 percent.