Answer:
Let X = score of final exam.
X~normal(23, 16)
(a)
percentage of score between 19 and 27
= P(19 < X < 27)
= P((19-23) / sqrt(16) < Z < (27 - 23) / sqrt(16))
= P(-1 < Z < 1)
= 1 - P(Z <= -1) - P(Z >= 1)
= 1 - P(Z >= 1) - P(Z >= 1)
= 1 - 2*P(Z >= 1)
= 1 - 2(0.1587)
= 0.6826
= 68.26%
According to Normal Distribution Table
P(Z>=1) = 1 - P(Z<1) = 1-0.8413
So the final percentage is 68.26%
¹/₈(16k - 24) + ¹/₅(2 + 10k)
¹/₈(16k) + ¹/₈(-24) + ¹/₅(2) + ¹/₅(10k)
2k + (-3) + ²/₅ + 2k
2k - 3 + ²/₅ + 2k
2k + 2k - 3 + ²/₅
4k - 2³/₅
2(x-6y+4z=2)
2x+4y-8z=16
2x-12y+8z=4
2x+4y-8z=16
4x-8y=20
x-2y=5
4x-8y=20
-4x+8y=-20
infinite many solutions
Answer:
270.63
Step-by-step explanation:
hope you get it right
The length is (3/5 -1/5)=2/5
the height is also 2/5
area: length * height =2/5 *2/5=4/5
D is correct.
