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Wittaler [7]
4 years ago
6

a horizontal force of 2500 N is applied for a time of 30 seconds to the car mass of 1000 kg if the car is at rest and friction i

s negligible determine the distance travelled by the car​
Physics
1 answer:
Digiron [165]4 years ago
6 0

Newton’s second law: F=ma. 2500=1000a. a=2.5m/s*s. Final velocity is 2.5*30=75m/s. Average speed is (Vi+Vf)/2, which is 37.5m/s. D=vt. 37.5*30=1125m. The distance traveled is 1125 meters

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HOPE THIS HELPS YOU MATE!!
I HAVE ALSO GIVEN THE EXPLANATION THINKING THAT IT MIGHT HELP YOU.
THANK YOU.
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larisa86 [58]

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3 years ago
A yo‑yo with a mass of 0.0800 kg and a rolling radius of =2.70 cm rolls down a string with a linear acceleration of 5.70 m/s2.
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Explanation:

Given that,

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3 0
3 years ago
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Katyanochek1 [597]
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