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tekilochka [14]
3 years ago
13

Suppose the sun were to suddenly disappear. what would happen to the orbital path of earth? it would stay the same, but the eart

h would speed up. it would stay the same, but the earth would slow down. it would follow a path perpendicular to the radius of its current orbit. it would spiral outward in an ever-increasing orbit.
Physics
2 answers:
GenaCL600 [577]3 years ago
8 0

Answer:

it would follow a path perpendicular to the radius of its current orbit

Explanation:

Currently, the Sun provides (with its gravitational attraction) the centripetal force that keeps the Earth in circular orbit around the Sun. The velocity of the Earth is always tangential to this orbit, while the centripetal force is directed towards the centre of the trajectory, therefore it is parallel to the radius of the orbit (which is perpendicular to the velocity of the Earth).

If the Sun suddenly disappears, then the centripetal force disappears. As a result, due to the law of the inertia, the Earth will continue its motion in a straight path, keeping its constant velocity (because there are no more forces that keep it along the circular trajectory): and since the velocity of the Earth was perpendicular to the radius of its previous orbit, the correct answer is

it would follow a path perpendicular to the radius of its current orbit

Vilka [71]3 years ago
7 0
C: It would follow a path perpendicular to the radius of its current orbit

When there is nothing to keep it going in circles, it will stop moving in circles around the sun and continue in a straight path. Think of it as a catapult. If the stick stops, the rock keeps flying straight at the speed and direction it was flung.
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Which person ha the most freedom to make his or her own lifestyle decisions?
alex41 [277]

Answer:

C Quincy

Explanation:

Both Frieda and Vladimir are too young to be making their own decisions. Lucinda has limited freedom due to having two children, while Quincy is just now becoming an adult and has his whole life still ahead of him. Therefore, Quincy has the most freedom to make their own lifestyle decisions.

I hope this helps!

3 0
2 years ago
As a person squeezes and applies pressure to the outside of a balloon air particles inside
MAVERICK [17]
They will occupy less volume which will cause an increased density of the particles.
3 0
3 years ago
A 5.75 mm high firefly sits on the axis of, and 11.3 cm in front of, the thin lens A, whose focal length is 5.77 cm . Behind len
weeeeeb [17]

Answer

given,

focal length of lens A = 5.77 cm

focal length of lens B= 27.9 cm

flies distance from mirror = 11.3 m

now,

Using lens formula

\dfrac{1}{f} = \dfrac{1}{p} + \dfrac{1}{q}

\dfrac{1}{5.77} = \dfrac{1}{11.3} + \dfrac{1}{q}

q =11.79 cm

image of lens A is object of lens B

distance of lens = 59.9 - 11.79 = 48.11

now, Again applying lens formula

\dfrac{1}{f} = \dfrac{1}{p} + \dfrac{1}{q'}

\dfrac{1}{27.9} = \dfrac{1}{48.11} + \dfrac{1}{q'}

q' =66.41 cm

hence, the image distance from the second lens is equal to q' =66.41 cm

6 0
2 years ago
Two protons are maintained at a separation of nm. Calculate the electric potential due to the two particles at the midpoint betw
Liono4ka [1.6K]

Answer:

The electric potential is approximately 5.8 V

The resulting direction of the electric field will lie on the line that joins the charges but since it is calculated in the midpoint and the charges are the same we can directly say that its magnitude is zero

Explanation:

The two protons can be considered as point charges. Therefore, the electric potential is given by the point charge potential:

\displaystyle{U=\frac{q}{4\pi \epsilon_0r}} (1)

where q is the charge of the particle, \epsilon_0 the electric permittivity of the vacuum (I assuming the two protons are in a vacuum) and r is the distance from the point charge to the point where the potential is being measured. Because the electric potential is an scalar, we can simply add the contribution of the two potentials in the midpoint between the protons. Thus:

\displaystyle{U_{midpoint}=\frac{q}{4\pi \epsilon_0r}}+\frac{q}{4\pi \epsilon_0r}}=\frac{q}{2\pi \epsilon_0r}}}

Substituting the values q=1.602 \cdot10^{-19}\ C, \displaystyle{\frac{1}{4\pi\epsilon_0}=8.99\cdot 10^9 N\cdot m^2\cdot C^{-2}} and r=0.5 \cdot 10^{-9} m we obtain:

\displaystyle{U_{midpoint}=\frac{q}{2\pi \epsilon_0r}}=5.759 \approx 5.8 V}

The resulting direction of the electric field will lie on the line that joins the charges but since it is calculated in the midpoint and the charges are the same we can directly say that its magnitude is zero.

6 0
3 years ago
A new restaurant is interested in determining the best time-temperature combination for roasting a five-pound cut of lamb. The t
Leto [7]

Answer:

C

Explanation:

(c) The two cuts that are being roasted for each time-temperature combination are an example of replication.

In the question it is given that  From 10 identical cuts of lamb, 2 are randomly selected to roast using each of the time-temperature combinations in the same oven. Here it is an act of copying the exact sahpe size of the lamb in all cuts, which is nothing but replication. Moreover, this replication can help in proper comparision.

7 0
3 years ago
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