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tekilochka [14]
3 years ago
13

Suppose the sun were to suddenly disappear. what would happen to the orbital path of earth? it would stay the same, but the eart

h would speed up. it would stay the same, but the earth would slow down. it would follow a path perpendicular to the radius of its current orbit. it would spiral outward in an ever-increasing orbit.
Physics
2 answers:
GenaCL600 [577]3 years ago
8 0

Answer:

it would follow a path perpendicular to the radius of its current orbit

Explanation:

Currently, the Sun provides (with its gravitational attraction) the centripetal force that keeps the Earth in circular orbit around the Sun. The velocity of the Earth is always tangential to this orbit, while the centripetal force is directed towards the centre of the trajectory, therefore it is parallel to the radius of the orbit (which is perpendicular to the velocity of the Earth).

If the Sun suddenly disappears, then the centripetal force disappears. As a result, due to the law of the inertia, the Earth will continue its motion in a straight path, keeping its constant velocity (because there are no more forces that keep it along the circular trajectory): and since the velocity of the Earth was perpendicular to the radius of its previous orbit, the correct answer is

it would follow a path perpendicular to the radius of its current orbit

Vilka [71]3 years ago
7 0
C: It would follow a path perpendicular to the radius of its current orbit

When there is nothing to keep it going in circles, it will stop moving in circles around the sun and continue in a straight path. Think of it as a catapult. If the stick stops, the rock keeps flying straight at the speed and direction it was flung.
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Answer C

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What is the repulsive force between two pith balls that are 8.00 cm apart and have equal charges of – 30.0 nC?
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Answer:

F=1.26*10^{-3}N

Explanation:

Assuming the pith balls as point charges, we can calculate the repulsive force between them, using Coulomb's law:

F=\frac{kq_1q_2}{d^2}

We observe that the magnitude of the electric force is directly proportional to the product of the magnitude of both signed charges(q_1,q_2) and inversely proportional to the square of the distance(d) that separates them.

Replacing the given values, where k is the Coulomb constant:

F=\frac{8.99*10^{9}\frac{N\cdot m^2}{C^2}(-30*10^{-9}C)(-30*10^{-9}C)}{(8*10^{-2}m)^2}\\F=1.26*10^{-3}N

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3 years ago
If two normal distributions each have the same mean, but one has a standard deviation of 1 and the other has a standard deviatio
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In comparison to a distribution with a standard deviation of 5, one has a curve with a higher peak. The variability will be greater the larger the standard deviation. It denotes increased variability in a distribution with a standard deviation of 5.

<h3>What do you mean by the term standard deviation?</h3>

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8 0
2 years ago
A sinusoidal transverse wave of amplitude ym = 8.4 cm and wavelength = 5.3 cm travels on a stretched cord. Find the ratio of the
Scilla [17]

Answer:

The ratio is 9.95

Solution:

As per the question:

Amplitude, y_{m} = 8.4\ cm

Wavelength, \lambda = 5.3\ cm

Now,

To calculate the ratio of the maximum particle speed to the speed of the wave:

For the maximum speed of the particle:

v_{m} = y_{m}\times \omega

where

\omega = 2\pi f = angular speed of the particle

Thus

v_{m} = 2\pi fy_{m}

Now,

The wave speed is given by:

v = f\lambda

Now,

The ratio is given by:

\frac{v_{m}}{v} = \frac{2\pi fy_{m}}{f\lambda}

\frac{v_{m}}{v} = \frac{2\pi \times 8.4}{5.3} = 9.95

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4 years ago
A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 × 104 meters. If the truck's mass is 7,000 kilograms, wha
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Work done = force * distance moved (in direction of the force)

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3 years ago
Read 2 more answers
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