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tekilochka [14]
3 years ago
13

Suppose the sun were to suddenly disappear. what would happen to the orbital path of earth? it would stay the same, but the eart

h would speed up. it would stay the same, but the earth would slow down. it would follow a path perpendicular to the radius of its current orbit. it would spiral outward in an ever-increasing orbit.
Physics
2 answers:
GenaCL600 [577]3 years ago
8 0

Answer:

it would follow a path perpendicular to the radius of its current orbit

Explanation:

Currently, the Sun provides (with its gravitational attraction) the centripetal force that keeps the Earth in circular orbit around the Sun. The velocity of the Earth is always tangential to this orbit, while the centripetal force is directed towards the centre of the trajectory, therefore it is parallel to the radius of the orbit (which is perpendicular to the velocity of the Earth).

If the Sun suddenly disappears, then the centripetal force disappears. As a result, due to the law of the inertia, the Earth will continue its motion in a straight path, keeping its constant velocity (because there are no more forces that keep it along the circular trajectory): and since the velocity of the Earth was perpendicular to the radius of its previous orbit, the correct answer is

it would follow a path perpendicular to the radius of its current orbit

Vilka [71]3 years ago
7 0
C: It would follow a path perpendicular to the radius of its current orbit

When there is nothing to keep it going in circles, it will stop moving in circles around the sun and continue in a straight path. Think of it as a catapult. If the stick stops, the rock keeps flying straight at the speed and direction it was flung.
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How fast must a 350 gram softball be traveling in order to have a momentum of .600 kg
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4 0
4 years ago
A car of mass 487 kg travels around a flat, circular race track of radius 53.3 m. The coefficient of static friction between the
aleksklad [387]

Answer:

9.96 m/s

Explanation:

mass of car, m = 487 kg

radius of track, R = 53.3 m

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acceleration due to gravity, g = 9.8 m/s^2

let v be the maximum speed so that the car can go without flying off the track.

The formula for the maximum speed is given by

v_{max}=\sqrt{\mu Rg}

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8 0
3 years ago
Waves that hit a fixed boundary return to the starting point on the____
Jet001 [13]

Answer:

A: Opposite

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3 0
3 years ago
A person on a rocket traveling at 0.47 c (with respect to the Earth) observes a meteor come from behind and pass her at a speed
zhannawk [14.2K]

The concept to solve this problem is related to the relativistic physics for which the speed of the object in different frames of reference is related. This concept is called Velocity-addition formula

and can be written as,

u = \frac{v+u'}{1+\frac{vu'}{c^2}}

Where,

u = Velocity of a body within a Lorentz Frame

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u'= The transformed velocity of the body within the second frame

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Replacing we have to

u = \frac{v+u'}{1+\frac{vu'}{c^2}}

u = \frac{0.47c+0.47c}{1+\frac{0.47c*0.47c}{c^2}}

u = 0.769c

u \approx 230'700.000m/s

Therefore the meteor moving with respect to the Earth to 230'700.000m/s

7 0
3 years ago
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