Which has more energy, a photon of ultraviolet radiation or a photon of yellow light?

a person hears an echo from the top of a tower , 2.2 second after the sound is produced.how far away is the tower from the perso

bekas [8.4K]

Answer:

730.4 m

Explanation:

The sound waves travels with a uniform motion (=constant velocity), therefore we can calculate the distance it travels using the formula:

$d=vt$

where

d is the distance

v is the speed of the sound wave

t is the time taken

In this problem we have:

v = 332 m/s is the speed of sound in air

t = 2.2 s is the time elapsed

Therefore, the distance between the tower and the person is

$d=(332)(2.2)=730.4 m$

5 0

3 years ago

Problem 6.056 Air enters a compressor operating at steady state at 15 lbf/in.2, 80°F and exits at 275°F. Stray heat transfer and

vova2212 [387]

To solve this process it is necessary to consider the concepts related to the relations between pressure and temperature in an adiabatic process.

By definition the relationship between pressure and temperature is given by

$(\frac{P_2}{P_1})=(\frac{T_2}{T_1})^{(\frac{\gamma}{\gamma-1})}$

Here

P = Pressure

T = Temperature

$\gamma =$ The ratio of specific heats. For air normally is 1.4.

Our values are given as,

$P_1 = 15lb/in^2\\T_1= 80\°F = 299.817K\\T_2 =400\°F = 408.15K$

Therefore replacing we have,

$(\frac{P_2}{P_1})=(\frac{T_2}{T_1})^{(\frac{\gamma}{\gamma-1})}$

$(\frac{P_2}{15})=(\frac{408.15}{299.817})^{(\frac{1.4}{1.4-1})}$

Solving for $P_2,$

$P_2 = 15*(\frac{408.15}{299.817})^{(\frac{1.4}{1.4-1})}$

$P_2 = 44.15Lbf/in^2$

Therefore the maximum theoretical pressure at the exit is $44.15Lbf/in^2$

5 0

3 years ago

. A car going 50 m/s accelerates to pass a truck. Five seconds later the car is going 80m/s. Calculate the acceleration of the c

sineoko [7]

6 mph/s

Calculating acceleration involves dividing velocity by time — or in terms of SI units, dividing the meter per second [m/s] by the second [s]. Dividing distance by time twice is the same as dividing distance by the square of time. Thus the SI unit of acceleration is the meter per second squared .

8 0

2 years ago

" A bowl of soup at 200Á F. is placed in a room of constant temperature of 60Á F. The

Dahasolnce [82]

T(t)=60+140e−0.075t T(12)=60+140e−0.075∗12 T(12)=60+140e−0.9 T(12)=60+140(0.4065696597)
=116.84
So the temperature will be approximately 117 degrees

7 0

3 years ago

A car goes around a curve of radius r at a constant speed v. Then it goes around a curve ofradius 2r at speed 2v. What is the ce

Rainbow [258]

The centripetal force on the car as it goes around the second curve is twice that compared to the first.

What is Centripetal force?

It is the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation.

The formula of Centripetal force is:

F(c) = (m* v^2) / r

Here,

At the first curve,

The curve of radius = r

The constant speed = v

At the second curve,

The car speed (v')= 2 v

The radius of the curve (r')=2 r

According to the formula of centripetal Force:

As the car goes around the second curve,

F'(c) = m*v'^2 / r'

F'(c) = m* (2*v)^2 / 2r

F'(c) = 2* F

Thus,

The centripetal force on the car as it goes around the second curve is twice that compared to the first.

Learn more about centripetal force here:

brainly.com/question/14317060

#SPJ4

8 0

1 year ago