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3 years ago

The cost of item A is $8 and the

Mathematics

2 answers:

yKpoI14uk [10]3 years ago

7 0

Answer: the number of item A that you sold is 11

the number of item B that you sold is 2

Step-by-step explanation:

Let x represent the number of item A that you sold.

Let y represent the number of item B that you sold.

The total number of item A and item B sold is 13. This means that

x + y = 13

The cost of item A is $8 and the

cost of item B is $4. The total amount if money made is $88. This means that

8x + 4y = 88 - - - - - - - - - -1

Substituting x = 13 - y into equation 1, it becomes

8(13 - y) + 4y = 88

104 - 8y = 88

8y = 104 - 88 = 16

y = 16/8 = 2

x = 13 - y = 13 - 2 = 11

melisa1 [442]3 years ago

5 0

Answer:

4 of item A, and 9 of item B

Step-by-step explanation:

Let x represent the number of item sold in A

Let y represent the number of item sold in B

If the total number of item sold is 13. This implies

x + y = 13

The cost of item A is $8, the cost of item B is $4 and if the total amount of money made is $88, this implies

8(x) + 4(y) = 88 (Substitue x = 13 - y)

→ 8(13 - y) + 4y = 88

→ 104 - 8y + 4y = 88

→ 4y = 16

→ y = 4

If y = 4, then x = 13 - y = 9

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Find an upper limit for the zeroes 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0

erik [133]

<u>Answer-</u>

2 is the upper limit for the zeros.

<u>Solution-</u>

The given function f(x) is,

$2x^4 -7x^3 + 4x^2 + 7x - 6 = 0$

For calculating the zeros,

$\Rightarrow f(x)=0$

$\Rightarrow 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0$

$\Rightarrow 2x^4-4x^3-3x^3+6x^2-2x^2+ 4x+3x-6=0$

$\Rightarrow 2x^3(x-2)-3x^2(x-2)-2x(x-2)+3(x-2)=0$

$\Rightarrow (x-2)(2x^3-3x^2-2x+3)=0$

$\Rightarrow (x-2)(x^2(2x-3)-1(2x-3))=0$

$\Rightarrow (x-2)(x^2-1)(2x-3)=0$

$\Rightarrow (x-2)(x+1)(x-1)(2x-3)=0$

$\Rightarrow x-2=0,\ x+1=0,\ x-1=0,\ 2x-3=0$

$\Rightarrow x=2,\ x=-1,\ x=1,\ x=\frac{3}{2}$

From all the 4 roots, it can be obtained that 2 is the greatest zero.

7 0

3 years ago

How to solve for 4(m - 2 ) = 24

tino4ka555 [31]

4(m - 2 ) = 24

Divide both sides by 4

m - 2 = 8

add 2 to both sides

m = 10

Hope this helps! ;)

3 0

3 years ago

Read 2 more answers

Find the equation of the parabola that passes through

valentinak56 [21]

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$\bf \begin{array}{cccllll} \stackrel{\textit{point (0,-7)}}{-7=a(0)^2+b(0)+c}& \stackrel{point (7,-14)}{-14=a(7)^2+b(7)+c}& \stackrel{point (-3,-19)}{-19=a(-3)^2+b(-3)+c}\\\\ -7=c&-14=49a+7b+c&-19=9a-3b+c \end{array}$

well, from the 1st equation, we know what "c" is already, so let's just plug that in the 2nd equation and solve for "b".

$\bf -14=49a+7b-7\implies -7=49a+7b\implies -7-49a=7b \\\\\\ \cfrac{-7-49a}{7}=b\implies \cfrac{-7}{7}-\cfrac{49a}{7}=b\implies -1-7a=b$

well, now let's plug that "b" into our 3rd equation and solve for "a".

$\bf -19=9a-3b-7\implies -12=9a-3b\implies -12=9a-3(-1-7a) \\\\\\ -12=9a+3+21a\implies -15=9a+21a\implies -15=30a \\\\\\ -\cfrac{15}{30}=a\implies \blacktriangleright -\cfrac{1}{2}=a \blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{and since we know that}}{-1-7a=b}\implies -1-7\left( -\cfrac{1}{2} \right)=b\implies -1+\cfrac{7}{2}=b\implies \blacktriangleright \cfrac{5}{2}=b \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-\cfrac{1}{2}x^2+\cfrac{5}{2}x-7~\hfill$

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3 years ago

kayla and Jane helped Mr.John fit kids in the auditorium. There was 603 kids,and each row can fit 31 kids. How many rows do they

olga2289 [7]

Answer:

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3 years ago

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mr_godi [17]

Answer:

see below

Step-by-step explanation:

In decimal, the values of the fractions are ...

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-2/8 = -0.250

So, in a, b, c order, they are ...

a = -3/7

b = -2/8

c = -0.2

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3 years ago