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Answer:
it is C the 4
Step-by-step explanation:
-6 to pos 4
Answer:
y=1
Step-by-step explanation:
2y+5y-7=0
Combine y: 7y-7=0
Move 7 over: 7y=7
Divide by 7:y=1
<span>Exactly 33/532, or about 6.2%
This is a conditional probability, So what we're looking for is the probability of 2 gumballs being selected both being red. So let's pick the first gumball.
There is a total of 50+150+100+100 = 400 gumballs in the machine. Of them, 100 of the gumballs are red. So there's a 100/400 = 1/4 probability of the 1st gumball selected being red.
Now there's only 399 gumballs in the machine and the probability of selecting another red one is 99/399 = 33/133.
So the combined probability of both of the 1st 2 gumballs being red is
1/4 * 33/133 = 33/532, or about 0.062030075 = 6.2%</span>
An equivalent expression would be s+15
You simplify the expression.
So yea the answer is s+15
