Answer:
Yes, the shapes are similar. Note, the angles are equivalent and the sides are scales of each other satisfying the requirements for similarly.
Step-by-step explanation:
For a shape to be similar there are two conditions that must be met. (1) Must have equivalent angles (2) Sides must be related by a scalar.
In the two triangles presented, the first condition is met since each triangle has three angles, 90-53-37.
To test if the sides are scalar, each side must be related to a corresponding side of the other triangle with the same scalar.
9/6 = 3/2
12/8 = 3/2
15/10 = 3/2
Alternatively:
6/9 = 2/3
8/12 = 2/3
10/15 = 2/3
Since the relationship of the sides is the scalar 3/2 (Alternatively 2/3), then we can say the triangles meet the second condition.
Given that both conditions are satisfied, then we can say these triangles are similar.
Note, this is a "special case" right triangle commonly referred to as a 3-4-5 right triangle.
Cheers.
5x + 2 -x = -4x
4x +2 = -4x
2 = -4x -4x
2 = -8x
x = - 1/4
hope this helps
200 dollars like the answer please
Answer:
The given linear equation are
⇒9x+3y+12=0....eq1
⇒a1
=9,b1
=3,c1
=12
⇒18x+6y+24...eq2
⇒a2
=18,b2
=6,c2
=24
⇒a1/a2
=9/18 =1/2
⇒ b1/b2= 3/6 = 1/2
⇒ c1/c2= 12/24= 1/2
comparing
⇒ a1/a2,b1/b2,c1/c2
⇒ a1/a2=b1/b2=c1/c2
Hence, the line represented by eq1 and eq2 are coincidents
Step-by-step explanation:
