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maria [59]
3 years ago
11

7b Evaluate when b= -1 b-3

Mathematics
1 answer:
tiny-mole [99]3 years ago
5 0

Answer:

b-3

-1-3

-4

is the correct answer

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In 2015, three wide receivers for the Arizona Cardinals caught a total of 226 passes. Larry Fitzgerald caught 44 more passes tha
Ugo [173]

Answer:

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Step-by-step explanation:

4 0
3 years ago
What number will the function return if the input is 15.4?
wlad13 [49]

The rule of the function is to multiply the input by 3, since one yard is equal in length to three feet.

So, if the input is 15.4, the output will be

f(x)=3x \implies f(15.4)=3\cdot 15.4 = 46.2

4 0
3 years ago
F(x) = x^2 and g(x) = 2x-3 What is the value of g(4) + f(-3)?
Komok [63]

Answer: 66

Step-by-step explanation:see attachment.

If this helps you please rate brainest

3 0
3 years ago
Describe how to transform:
Anna71 [15]

Answer:

x^\frac{35}{6}

Step-by-step explanation:

The expression to transform is:

(\sqrt[6]{x^5})^7

Let's work first on the inside of the parenthesis.

Recall that the n-root of an expression can be written as a fractional exponent of the expression as follows:

\sqrt[n]{a} = a^{\frac{1}{n}}

Therefore \sqrt[6]{a} = a^{\frac{1}{6}}

Now let's replace a with x^{5} which is the algebraic form we are given inside the 6th root:

\sqrt[6]{x^5} = (x^5)^{\frac{1}{6}}

Now use the property that tells us how to proceed when we have  "exponent of an exponent":

(a^n)^m= a^{n*m}

Therefore we get:  (x^5)^{\frac{1}{6}}=x^{\frac{5}{6}}}

Finally remember that this expression was raised to the power 7, therefore:

[tex](\sqrt[6]{x^5})^7=(x^\frac{5}{6})^7=x^\frac{35}{6}[/tex]

An use again the property for the exponent of a exponent:

8 0
3 years ago
GIVING BRAINLIEST!<br><br> Solve for y: 3x - y = 14<br><br> Thank you~
ValentinkaMS [17]
To solve y, we need to make y the only value on the left hand side of the equation:

3x - 3x - y = 14 \\  3x - 3x - y = 14 - 3x \\  - y = 14 - 3x \\ y =  - (14 - 3x) \\ y =  - 14 + 3x
Therefore the value of y = -14+3x.

Hope it helps!
8 0
3 years ago
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