Answer:
x=17
Step-by-step explanation:
Since the triangles are congruent, the angles are equal
I≅ P
3x+4 = 72-x
Add x to each side
3x+4+x = 72-x+x
4x+4 = 72
Subtract 4 from each side
4x+4-4 = 72-4
4x= 68
Divide by 4
4x/4 = 68/4
x = 17
Six. 2 1/3=7/3-> to get to have a denominator of 6 multiply by 2 to get 14/6
Then 1/2=3/6
14/6 + 3/6 = 17/6
17/6= 2 5/6
7^0=1
7^1=7
7^2=7*7=49
7^3=7*7*7=343
etc... etc...
We have a domain of a function, that is, which x-es can we throw in. But we are asking which y-s will we get given that we can only throw x-es in 
.
Let's try 
even though we are forbidden to put 4 inside 
we are still able to do so.
So 
what we just got is the upper limit of the range. The lower limit is 
.
So the range is just 
.
Hope this helps :)
Yes they will be parallel. Now you try to solve it.
