I got -3.6 m/s but I had to do conservation of momentum for this question. Which involves Newtons third law but with simply that law I do not know how to complete this question. If you would like me to post my work I will though! Sorry
E=Fe/q
5.8x10^5N/C=Fe/(1.5x10^-9C)
Fe=(5.8x10^5N/C)(1.5x10^-9C)
Fe=8.7x10^-4N
Fe=kq1q2/r²
8.7X10^-4N=(8.99x10^9N·m²/C²)(1.5x10^-9C)(1.5x10-9C)/r²
r²=(8.99x10^9N·m²/C²)(1.5x10^-9C)(1.5x10-9C)/(8.7x10^-4N)
√r²=√0.00002325
The final answer is r=4.8x10-3m
Here, E<span>ach kilogram of mass weighs 9.8 newtons as it's unit value of it.
In short, Your Answer would be Option D
Hope this helps!</span>
Kinetic energy = 1/2 m v²
If we reduce the mass by half > m/2
Kinetic energy = 1/2 m/2 v²
We should know that 1/2 × 1/2 = 1/4
So kinetic energy will be :
1/4 × m × v²
