Answer:
D. Cold, dry air
(Just took the quiz and got it right, hope this helps :3)
Answer:
Gravity
Explanation:
When the ball is falling to the ground, there is only one force- gravity. In some cases, there may be air resistance, but that seems to be neglected here.
Normal force:
Cannot be included. Normal force is only applicable when object is on a surface, and it acts perpendicular to the surface. Since the ball is falling, there is no surface, and therefore no normal force. This question gives you unnecessary information, designed to trick you. Please remember when normal force is applicable.
Friction force:
Also only applicable when object is moving, and is on the table. Friction only applies when there is an applied force. There is no applied force when the ball is falling, so therefore no friction force.
Force of fall:
First of all, what is this? There is nothing called force of fall.
Gravity:
This is the only one that applies. Just draw a vector arrow from the bottom of the ball and label it mg (acceleration due to gravity).
Answer:
0.34148 m
Explanation:
= Resistivity of tungsten =
d = Diameter = 0.0018 inch
r = Radius =
= Temperature coefficient of tungsten =
Power is given by
We have the equation
Resistance is given by
The length of the filament is 0.34148 m
Answer:
Given force=10lb
L1=4in converting to feet
But 0.08333ft= 1 inch
Then 4 inch is 0.3332
6inch is 0.49998
But hookes law states
F=Kx where F is force,K is the force constant ,X
K=F/X=10/0.3333=30N/m
Integrating this
Integral of 30x with limit 0.333 to 0.5
F=30x^2/2=15x^2substing the limit
F=(15(0.5^2-0.33^2)=2.08ft-lb
Explanation:
It seems like the question is asking for the frequency.
Given:
Time period (T) = 2.4 sec
Frequency (f) =?
We know that the formula for frequency is:
Frequency (f) = 1/time period (T)
= 1 / 2.4 s
= 0.42 Hz. is the frequency for this problem.