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2 years ago

FIRST ANSWER GETS BRAINLIST:

Physics

2 answers:

bezimeni [28]2 years ago

8 0

Object A and Object B...

Natalka [10]2 years ago

3 0

Answer:

Object A but not Object B

You might be interested in

How far will an object move in 6 s if its average

Dafna11 [192]

Given:-

Time taken by the particle (t) = 6 s
Average speed (v) = 40 m/s

To Find: Distance (s) travelled by the particle.

We know,

s = vt

where,

s = Distance travelled,
v = Speed &
t = Time taken.

Putting the values,

s = (40 m/s)(6 s)

→ s = 240 m ...(Ans.)

6 0

3 years ago

Consider a concave spherical mirr or that has focal length f = +19.5 cm.

lidiya [134]

The distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.

<h3>What is concave mirror?</h3>

A concave mirror has a reflective surface that is curved inward and away from the light source.

Concave mirrors reflect light inward to one focal point and it usually form real and virtual images.

<h3>Object distance of the concave mirror</h3>

Apply mirrors formula as shown below;

1/f = 1/v + 1/u

where;

f is the focal length of the mirror
v is the object distance
u is the image distance

when image height = object height, magnification = 1

u/v = 1

v = u

Substitute the given parameters and solve for the distance of the object from the mirror's vertex

1/f = 1/v + 1/v

1/f = 2/v

v = 2f

v = 2(19.5 cm)

v = 39 cm

Thus, the distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.

Learn more about concave mirror here: brainly.com/question/27841226

#SPJ1

7 0

1 year ago

A calorimeter is used to determine the specific heat capacity of a test metal. If the specific heat capacity of water is known,

denis23 [38]

Answer:

initial and final temperatures of both the water and metal, mass of the metal, and mass of the water

Explanation:

Heat lost by the metal, $Q = mc(t_{2} - t_{1})$

Heat gained by the water in the calorimeter, $Q_{w} = m_{w}c_{w}(t_{2w} - t_{1w})$

For energy to be conserved in the system, the heat lost by the metal will equal the heat gain by the water in the calorimeter.

$mc(t_{2} - t_{1}) = m_{w}c_{w}(t_{2w} - t_{1w})$

Where,

m is the mass of the metal

c is specific heat capacity of the metal

t₂ is the final temperature of the metal

t₁ is the initial temperature of the metal

$m_{w}$ is the mass of the water

$c_{w}$ is specific heat capacity of water

$t_{2w}$ is the final temperature of water

$t_{1w}$ is the initial temperature of water

From the question given, specific heat capacity of the water is known, the quantities to be measured are;

Initial and final temperatures of both the water and metal,

Mass of the metal, and mass of the water

8 0

3 years ago

How many grams of CO2 are in 10 mol of the compound?

Zepler [3.9K]

For our problem, this means that one mole of CO2 has a mass of 44.01 grams. So 22 grams divided by 44.01 grams is roughly 0.5 moles of CO2.

hope it helps

4 0

3 years ago

~~~~~NEED HELP ASAP~~~~~

Romashka-Z-Leto [24]

Answer:

Centripetal Acceleration 18.75 m/s^2, Rotational Kinetic Energy 843.75 J

Explanation:

a Linear acceleration (we cant find tangential acceleration with the givens so we will find centripetal)

a= ω^2*r

ω= 300rev/min

convert into rev/s

300/60= 5rev/s

a= 18.75m/s^2

b) use Krot= 1/2 Iω^2

plug in gives

1/2(30*2.25)(25)= 843.75 J

8 0

2 years ago