14, 18, 22, 26, 30, . . . = 14, 14 + 4, 14 + 8, 14 + 12, 14 + 16, . . . = 14, 14 + 1(4), 14 + 2(4), 14 + 3(4), 14 + 4(4), . . . = 14 + 4(n - 1) = 14 + 4n - 4 = 4n + 10
Answer:
225.78 grams
Step-by-step explanation:
To solve this question, we would be using the formula
P(t) = Po × 2^t/n
Where P(t) = Remaining amount after r hours
Po = Initial amount
t = Time
In the question,
Where P(t) = Remaining amount after r hours = unknown
Po = Initial amount = 537
t = Time = 10 days
P(t) = 537 × 2^(10/)
P(t) = 225.78 grams
Therefore, the amount of iodine-131 left after 10 days = 225.78 grams
Answer:
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5 because it says 11-16 which is one number before 15. dollars