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Flura [38]
3 years ago
6

In which situation will the friction between an object and the surface on which it is moving be decreased?

Physics
1 answer:
Svetradugi [14.3K]3 years ago
3 0
Option d is correct.
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The magnetic field strength at the north pole of a 2.0-cm-diameter, 8-cm-long Alnico magnet is 0.10 T. To produce the same field
Sonbull [250]

Answer:

The number of turns of the solenoid is 3536 turns

Explanation:

Given;

magnetic field of the solenoid, B = 0.1 T

current in the solenoid, I = 1.8 A

length of the solenoid, L = 8cm = 0.08m

The magnetic field near the center of the solenoid is given by;

B = μ₀nI

Where;

μ₀ is permeability of free space = 4π x 10⁻⁷ m/A

n is number of turns per length

I is the current in the coil

The number of turns per length is calculated as;

n = B / μ₀I

n = (0.1 ) / (4π x 10⁻⁷ x 1.8)

n = 44203.95 turns/m

The number of turns is calculated as;

N = nL

N = (44203.95)(0.08)

N = 3536 turns

Therefore, the number of turns of the solenoid is 3536 turns

7 0
4 years ago
What are the different intensity of an earthquake
Masja [62]

Ranking Earthquake Intensity

Magnitude Average number per year Modified Mercalli Intensity

2.0 – 2.9 >1 million I

3.0 – 3.9 about 100,000 II – III

4.0 – 4.9 about 10,000 IV – V

5.0 – 5.9 about 1,000 VI – VII

Explanation:

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5 0
3 years ago
Two particles move along an x axis. The position of particle 1 is given by x ! 6.00t 2 # 3.00t # 2.00 (in meters and seconds); t
s344n2d4d5 [400]

Answer:

15.6m/s

Explanation:

V1=\frac{dx}{dt}=\frac{d}{dt}(6t^{2}+3t+2) because the derivate of the position is the velocity

V1=12t+3

V2=20+\int\limits^_ {} \,-8t because the integral of the acceleration is the velocity

V2=20-4t^{2}

V1=V2 to see when the velocities of particles match

12t+3=20-4t^2

4t^2+12t-17=0 we resolve this with \frac{-b+-(\sqrt{b^{2} -4ac} )}{2a}

and we take the positif root

t=1.05 sec

if we evaluate the velocity (V1 or V2) the result is 15.6m/s

7 0
3 years ago
Two identical 0.400 kg masses are pressed against opposite ends of a light spring of force constant 1.75 N/cm, compressing the s
nlexa [21]

Answer:

0.853 m/s

Explanation:

Total energy stored in the spring = Total kinetic energy of the masses.

1/2ke² = 1/2m'v².................... Equation 1

Where k = spring constant of the spring, e = extension, m' = total mass, v = speed of the masses.

make v the subject of the equation,

v = e[√(k/m')].................... Equation 2

Given: e = 39 cm = 0.39 m, m' = 0.4+0.4 = 0.8 kg, k = 1.75 N/cm = 175 N/m.

Substitute into equation 2

v = 0.39[√(1.75/0.8)

v = 0.39[2.1875]

v = 0.853 m/s

Hence the speed of each mass = 0.853 m/s

7 0
3 years ago
Simple Harmonic Motion Problems:
inessss [21]

Find the answer in the attachment

5 0
4 years ago
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