Explanation:
Below is an attachment containing the solution.
Answer:
C) gravity separated from the unified force, strong force separated from the unified force, inflationary expansion occurred, electromagnetic and weak forces separated from the unified force, quarks and electrons formed
All of the given options represent NASA future projects:
- Use a probe to collect data- Parker Solar Probe will be the first-ever mission to study the Sun from such a small distance. The spacecraft will travel directly into the Sun's atmosphere about 4 million miles from the surface.
- Improve aviation technology- NASA is currently working on the development of the new experimental aircraft X-plane which will prove the dramatic benefits of advanced technologies in piloted flight.
- Conduct research from a space station- Humans are already living and working on board of the International Space Station which is one-of-a-kind research laboratory in microgravity. A portion of the astronauts time aboard the space station has been designated for national laboratory investigations.
- Collect samples on an asteroid- First asteroid sample return mission, OSIRIS-REx, arrives at the near-Earth asteroid Bennu in December 2018 and should return a sample for study in 2023.
- Conduct an unmanned space mission- InSight Mars lander is set to study the planet’s interior. The Mars 2020 rover will search for signs of past microbial life, gather samples for future return to Earth and investigate resources. The James Webb Space Telescope will be the premier observatory of the next decade, studying every phase in the history of our Universe in infrared
Answer:
A) ΔU = 3.9 × 10^(10) J
B) v = 8420.75 m/s
Explanation:
We are given;
Potential Difference; V = 1.3 × 10^(9) V
Charge; Q = 30 C
A) Formula for change in energy of transferred charge is given as;
ΔU = QV
Plugging in the relevant values gives;
ΔU = 30 × 1.3 × 10^(9)
ΔU = 3.9 × 10^(10) J
B) We are told that this energy gotten above is used to accelerate a 1100 kg car from rest.
This means that the initial potential energy will be equal to the final kinetic energy since all the potential energy will be converted to kinetic energy.
Thus;
P.E = K.E
ΔU = ½mv²
Where v is final velocity.
Plugging in the relevant values;
3.9 × 10^(10) = ½ × 1100 × v²
v² = [7.8 × 10^(8)]/11
v² = 70909090.9090909
v = √70909090.9090909
v = 8420.75 m/s