Answer:
<em>-1</em>
Step-by-step explanation:
1. A water wheel rung’s height as a function of time can be modeled by the equation:
h - 8 = -9 sin6t
(b) Determine the maximum height above the water for a rung.
Given the rung's height modeled by the equation;
h - 8 = -9 sin6t
h(t) = -9sin6t + 8
At maximum height, the velocity of the rung is zero;
dh/dt = 0
dh/dt = -54cos6t
-54cos6t = 0
cos6t = 0/-54
cos6t = 0
6t = cos^-1(0)
6t = 90
t = 90/6
t= 15
Substitute t = 15 into the expression to get the maximum height;
Recall:
h(t) = -9sin6t + 8
h(15) = -9sin6(15) + 8
h(15) = -9sin90 + 8
h(15) = -9(1)+8
h(15) = -9+8
<em>h(15) = -1</em>
<em>hence the maximum height above the water is -1</em>
25% 3/10 1/3 and 37.5%
.25,.30,.33,.375
Answer:
g=3 yards
Step-by-step explanation:
Since the 3yd on the big triangle is reduced to 1 yd on the small triangle divide 9 by 3 to get the missing side length of 3 yards. Hope this helps :)
Answer:
y=-2/3x+20/3
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(4-6)/(4-1)
m=-2/3
y-y1=m(x-x1)
y-6=-2/3(x-1)
y=-2/3x+2/3+6
y=-2/3x+2/3+18/3
y=-2/3x+20/3
3 of 5 because you can halve each number for example 6 can be halved to make 3 and 10 can be halved to make 5