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serious [3.7K]
3 years ago
10

Consider two wheels with fixed hubs. The hub cannot move, but the wheel can rotate about it. The hubs are fixed to a stationary

object. The hubs and spokes are massless, so that the moment of inertia of each wheel is given by I = mr2 , where r is the radius of the wheel. Each wheel starts from rest and has a force applied tangentially at its rim. Wheel A has a mass of 1.0 kg, a diameter of 1.0 m, and an applied force of 1.0 N. Wheel B has a mass of 1.0 kg and a diameter of 2.0 m. The two wheels undergo identical angular accelerations. What is the magnitude of the force applied to wheel B?
Physics
1 answer:
kykrilka [37]3 years ago
3 0

Answer:

Magnitude of force on wheel B is 4 N

Explanation:

Given that

I=mr^2

For wheel A

m= 1 kg

d= 1 m,r= 0.5 m

F=1 N

We know that

T= F x r

T=1 x 0.5 N.m

T= 0.5 N.m

T= I α

Where I is the moment of inertia and α is the angular acceleration

I_A=1 \times 0.5^2\ kg.m^2

I_A=0.25\ kg.m^2

T= I α

0.5= 0.25 α

\alpha = 2\ rad/s^2

For Wheel B

m= 1 kg

d= 2 m,r=1 m

I_B=1 \times 1^2\ kg.m^2

I_B=1 \ kg.m^2

Given that angular acceleration is same for both the wheel

\alpha = 2\ rad/s^2

T= I α

T= 1 x 2

T= 2 N.m

Lets force on wheel is F then

T = F x r

2 = F x 1

So F= 2 N

Magnitude of force on wheel B is 2 N

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Answer:

F = 98 N

Explanation:

Data:

  • Mass (m) = 14 kg
  • Acceleration (a) = 7 m/s²
  • Force (F) = ?

Use formula:

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Replace:

  • F = 14 kg * 7 m/s²

Multiply both operations, with the units:

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3 years ago
Salmon often jump waterfalls to reach their
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Answer:

6.35 m/s

Explanation:

The motion of the salmon is equivalent to that of a projectile, which consists of two independent motions:

- A horizontal motion with constant speed

- A vertical motion with constant acceleration (g=-9.8 m/s^2, acceleration of gravity)

The horizontal velocity of the salmon is given by:

v_x = u cos \theta

where

u = ? is the initial speed

\theta=32^{\circ} is the angle of projection

Then the horizontal distance covered by the salmon after a time t is given by

d=v_x t =(u cos \theta) t

Or equivalently, the time taken to cover a distance d is

t=\frac{d}{u cos \theta} (1)

Along the vertical direction, the equation of motion is

h = (u sin \theta) t + \frac{1}{2}gt^2 (2)

where

u sin \theta is the initial vertical velocity

If we substitute (1) into (2), we get:

h = (u sin \theta) \frac{d}{cos \theta} + \frac{1}{2}g(\frac{d}{ ucos \theta})^2=d tan \theta + \frac{gd^2}{2u^2 cos^2 \theta}

We now that in order to reach the breeding grounds, the salmon must travel a distance of

d = 2.02 m

reaching a height of

h = 0.574 m

Substituting these data into the equation and solving for u, we find the initial speed that the salmon must have:

u =\sqrt{ \frac{gd^2}{2(h-d tan \theta) cos^2 \theta}}=\sqrt{\frac{(-9.8)(2.02)^2}{2(0.574-(2.02)(tan 32))(cos^2(32))}}=6.35 m/s

8 0
3 years ago
Use the drop-down menus to complete the
bagirrra123 [75]

Answer:

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Explanation:

5 0
4 years ago
A 3.0 kg rifle is held firmly by a 50.0 kg woman, initially standing still. A 0.06 kg bullet leaves the rifle muzzle with a velo
ohaa [14]

Answer:

48kg

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7 0
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A same-size iron ball and wooden ball are dropped simultaneously from a tower and reach the ground at the same time. The iron ba
Papessa [141]

Answer:

momentum of iron ball is greater than wooden ball

Explanation:

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we know that momentum is defined as

P=Mv

and we know also that mass of iron ball is greater than mass of wooden ball and they reached on ground at same time  and same distance it mean also velocity will be same for both ball. therefore from above relation we have

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momentum of iron ball is greater than wooden ball

5 0
4 years ago
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